Hi,
ilCactuss wrote:Im stuck on this grid. Double checked It twice
Does anyone know the best advacend technique to solve It?
After elimination of the 2b1 with alignment 2r2C12, it can be solved as follows, with an
anti-track :
P'(3r8c2) : -3r8c2->7r8c2->7r7c4->9r9c4->8r9c5->2r1c5->3r1c7 => -3r1c2 => solution.
This is equivalent to the following AIC:
(3=7)r8c2-7r8c4=7r7c4-9r7c4=9r9c4-8r9c4=(8-2)r9c5=2r1c5-(2=3)r1c7 which means that 3r8c2 and 3r1c7 are strongly linked, so 3r1c2 which sees these two candidates can be eliminated.
Robert