Hud wrote:Pappocom sumarily rejects this puzzle so it will require advanced techniques to solve. It seems that Suboku for dummies isn't for dummies after all. I'll guarantee you someone on this forum can solve it though (unless it has multiple answers).
Pappocom rejects *lots* of puzzles, some of which are demonstrably trivial. This puzzle, though requiring a single somewhat advanced tactic, is NOT a difficult puzzle. Even if there were no community to share tactics, most bright enthusiasts would figure out this type of deduction, assuming they use pencilmarks.
Pencil marks will be needed for most people to finish this puzzle.
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7 1 3 | 8 9 2 | . . 4
4 2 8 | 6 5 7 | 9 3 1
. . . | . 4 . | 2 7 8
-------+-------+------
. 4 7 | 2 . 8 | 3 . .
8 . . | 7 . 5 | 4 . 2
. . 2 | 9 . 4 | 8 1 7
-------+-------+------
2 . 9 | . 8 . | 7 4 .
. 8 . | 4 7 . | . 2 9
6 7 4 | 5 2 9 | 1 8 3
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7 1 3 | 8 9 2 | 56 56 4
4 2 8 | 6 5 7 | 9 3 1
59 569 56 | 13 4 13 | 2 7 8
----------------+----------------+----------------
1x59 4 7 | 2 16 8 | 3 +569 +56
8 369 16 | 7 136 5 | 4 69 2
35 356 2 | 9 36 4 | 8 1 7
----------------+----------------+----------------
2 35 9 | 13 8 136 | 7 4 56
135 8 15 | 4 7 136 | 56 2 9
6 7 4 | 5 2 9 | 1 8 3
The only places for a 5 in box 6 are the two cells (marked with +) r4c89. This excludes the 5 from r4c1 (marked with x)
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7 1 3 | 8 9 2 | 56 56 4
4 2 8 | 6 5 7 | 9 3 1
59 569 56 | 13 4 13 | 2 7 8
----------------+----------------+----------------
+19 4 7 | 2 16 8 | 3 569 56
8 36x9 +16 | 7 136 5 | 4 +69 2
35 356 2 | 9 36 4 | 8 1 7
----------------+----------------+----------------
2 35 9 | 13 8 136 | 7 4 56
135 8 15 | 4 7 136 | 56 2 9
6 7 4 | 5 2 9 | 1 8 3
Now there is an xy-wing:
r5c8=9 => r5c2<>9
r5c8=6 => r5c3=1 => r4c1=9 => r5c2<>9
Therefore, r5c2<>9.
After this, the rest of the puzzle can be solved with single elimination, starting with r4c1=9.
- Code: Select all
7 1 3 | 8 9 2 | 56 56 4
4 2 8 | 6 5 7 | 9 3 1
59 569 56 |+13 4 +13 | 2 7 8
----------------+----------------+----------------
159 4 7 | 2 16 8 | 3 569 56
8 369 16 | 7 136 5 | 4 69 2
35 356 2 | 9 36 4 | 8 1 7
----------------+----------------+----------------
2 35 9 |+13 8 x136 | 7 4 56
135 8 15 | 4 7 136 | 56 2 9
6 7 4 | 5 2 9 | 1 8 3
Above is an even better solution:
r37c46 form a UNIQUE RECTANGLE. If r7c6 were [13], the puzzle would have two solutions. This is not allowed, therefore, r7c6 MUST BE 6. (Remember, unique rectangles must be in TWO rows, TWO columns and TWO boxes or they don't work.)
After this placement, the rest is trivial.