Stuck....need more advanced techniques

Advanced methods and approaches for solving Sudoku puzzles

Stuck....need more advanced techniques

Postby welshguy » Wed Oct 12, 2005 7:30 pm

Hi, fairly new to sudoku (havent failed yet, but this one has me foxed...)what techniques can i use to solve this puzzle (it's a super sudoku from the Times)

{3}{1}{59}{258}{4}{7}{89}{289}{6}
{59}{24}{6}{258}{3}{258}{1}{2489}{7}
{8}{7}{24}{6}{9}{1}{24}{5}{3}
{14}{5}{148}{48}{2}{3}{6}{7}{9}
{7}{248}{3}{9}{1}{6}{5}{24}{248}
{6}{9}{248}{7}{5}{48}{248}{3}{1}
{49}{3}{489}{1}{6}{249}{7}{2489}{5}
{1459}{46}{7}{245}{8}{2459}{3}{12469}{24}
{2}{468}{1459}{3}{7}{459}{49}{1469}{48}

would appreciate any advice and guidance
welshguy
 
Posts: 4
Joined: 12 October 2005

Postby Lummox JR » Wed Oct 12, 2005 8:04 pm

You have hidden pairs in box 7 and column 8. Once they're eliminated, the puzzle can be finished with singles alone.

If you haven't used hidden pairs before, I can show you how to find the pair in box 7. In this case you have the following candidates in that box:
Code: Select all
49    .     489
1459  46    .
.     468   14589

Notice the 1 can only go in two places. The 5 can only go in those same two places. Therefore, since one must be the 1 and one must be the 5, no other candidates will work there.
Code: Select all
49    .     489
15    46    .
.     468   15

Armed with that you should be able to find the one in column 8.
Lummox JR
 
Posts: 125
Joined: 22 September 2005

Postby welshguy » Wed Oct 12, 2005 8:23 pm

got it...thanks very much....sometimes you just need a good example to make things clear
welshguy
 
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Joined: 12 October 2005

Postby welshguy » Thu Oct 13, 2005 10:37 am

ok, i see the hidden pair in box seven. the 1 and the 5 are unique, however in column 8 i have {248}{24}{48}.
With the 4 being common to all three candidates, there are no unique pairs. Am I looking at this the wrong way?
welshguy
 
Posts: 4
Joined: 12 October 2005

Postby Karyobin » Thu Oct 13, 2005 10:52 am

Without solving the puzzle myself, the example you just posted is a Naked Triple and works just the same way as a Naked/Hidden Pair, i.e. you can often exclude some candidates when you find one.
Karyobin
 
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Postby Lummox JR » Thu Oct 13, 2005 6:43 pm

The way you're looking at it is not wrong, although it is in the wrong column. That's a naked triple in column 9, but it won't do you much good because those are the only cells in that column that aren't already filled. Column 8 has six unfilled cells, and there is definitely a hidden pair there. You could also look in just box 9, because the pair can be found there as well.
Lummox JR
 
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Joined: 22 September 2005

Postby welshguy » Fri Oct 14, 2005 4:52 pm

now I have established the difference between columns 8 & 9 (don't you just feel an idiot sometimes?). Yes I can see what u mean...thanks again
welshguy
 
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Postby Hanyou Hottie » Sat Oct 15, 2005 8:58 pm

I was wondering if I could get some help with spotting hidden pairs. I ask this because I actually found the naked quad in column 8 first (r1c8, r2c8, r5c8, and r7c8), instead of finding the hidden pair. It's true that this ended up eliminating the same candidates that the hidden pair would have, but it seems like finding a pair should be easier than finding a quad. Any tips on this subject?
Hanyou Hottie
 
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Joined: 15 October 2005

Postby PaulIQ164 » Sun Oct 16, 2005 8:23 pm

Yeah, they're two sides of the same coin, so there's always a hidden something and a naked something that together make up all the remaining cells in the row/col/box. Whichever you find, they do the same thing.
PaulIQ164
 
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