This puzzle came up in the Non Pappocom thread. This explains the colouring.
Look for conjugate pairs just 2 of that number in any row, column or box. Label the numbers alternately say red and blue. Because theyre pairs,
either the reds
or the blues will be correct.
The first rule is that if you find two of the same colour in the same group then they are the incorrect ones.
The second rule is that if you find an uncoloured candidate that intersects with a red and a blue that is also incorrect (that doesn't happen in this case).
- Code: Select all
. . . | . 1r . | 1b . .
. . . | . . . | . . .
. . . | . . 1b | . . 1r
-------------+------------+------------
. . . | . . . | . . .
. . . | . . . | . . .
. . . | . . . | . . .
-------------+------------+------------
. . . | . 1r | . . 1b
. . . | . . . | . . .
. . . | . 1 1r | 1r . .
Since two reds end up in same group - both box 8 and row 9 - they must be false and you can eliminate all the red 1s.