Sample very hard.sud

Advanced methods and approaches for solving Sudoku puzzles

Sample very hard.sud

Postby smh » Mon Jun 13, 2005 2:46 pm

I tried to solve the Sample Very Hard that comes with the program.

Code: Select all
8**|**1|*3*
**1|8**|**4
***|9**|*7*
-----------
*5*|**9|6**
*4*|***|*5*
**9|7**|*4*
-----------
*8*|**2|***
3**|**5|9**
*2*|1**|**5


I can get to the following after which i'm stuck.

Code: Select all
89*|5*1|236
**1|8**|594
***|9**|*7*
-----------
*5*|**9|6**
*4*|***|*59
**9|75*|*4*
-----------
*8*|**2|***
3**|**5|9**
*2*|1**|**5


I cheated and tried a solver. It came to the same point as i did before reporting it couldn't be solved by logic. It could solve it by guessing though.

Can this one be solved with logic?
smh
 
Posts: 4
Joined: 13 June 2005

Postby Animator » Mon Jun 13, 2005 3:04 pm

It sure can be solved by logic... So I guess it's time you start using a better solver:)

The key to solving it is column 1.

There are two group of numbers. One group has the numbers 4, 5, 6, and the other one has the numbers 1, 2, 6, 7.

If you figure out what that means then you will see that the only place for the number 1 in column 1 is in box 4. This leaves only one place for the number 1 in box 9.
Animator
 
Posts: 469
Joined: 08 April 2005

Postby smh » Mon Jun 13, 2005 4:01 pm

Animator wrote:It sure can be solved by logic... So I guess it's time you start using a better solver:)


It was just an online one. I liked it coz it showed me step by step.

Animator wrote:The key to solving it is column 1.

There are two group of numbers. One group has the numbers 4, 5, 6, and the other one has the numbers 1, 2, 6, 7.

If you figure out what that means then you will see that the only place for the number 1 in column 1 is in box 4. This leaves only one place for the number 1 in box 9.


Thanks.

I've been trying for the last 45 minutes but i can't seem to find what you mean with the two groups. A small hint is greatly appreciated.
smh
 
Posts: 4
Joined: 13 June 2005

Postby Animator » Mon Jun 13, 2005 8:14 pm

Hmm... I see that I made a mistake...

The first group is 4, 5, 9, and the second group is 1, 2, 6, 7.

The candidates for column 1:

r2c1: 2, 6, 7
r3c1: 2, 4, 5, 6
r4c1: 1, 2, 7
r5c1: 1, 2, 6, 7
r6c1: 1, 2, 6
r7c1: 1, 4, 5, 6, 7, 9
r9c1: 4, 6, 7, 9

I know it might be difficult to see the groups in there, so I'll add some candidates:

r2c1: 1, 2, 6, 7
r3c1: 2, 4, 5, 9, 6
r4c1: 1, 2, 6, 7
r5c1: 1, 2, 6, 7
r6c1: 1, 2, 6, 7
r7c1: 1, 4, 5, 6, 7, 9
r9c1: 4, 5, 6, 7, 9

Do you see the groups now? Where can the numbers 4, 5, 9 go? You have three numbers and the only candidate cells for them are the same three cells...

This basiclly means that they have to have that number, as in, try to fill in another number in r9c1 and see what happens...
Animator
 
Posts: 469
Joined: 08 April 2005

Postby angusj » Mon Jun 13, 2005 9:51 pm

I think a slightly easier way to tackle this is:

First: col3 where 467 must be in rows 1,8&9
Then: col1 where 7 must be in the middle block
angusj
 
Posts: 306
Joined: 12 June 2005

Postby Animator » Tue Jun 14, 2005 7:39 am

angusj is correct that there is also a group in column 3, which allows you to fill in the number 5 in that column.

As soon as I saw column 3 I reliased this question was already asked (and answered). Here is the other thread about this puzzle: http://forum.enjoysudoku.com/viewtopic.php?p=2295
Animator
 
Posts: 469
Joined: 08 April 2005


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