- Code: Select all
4 . . . . . . . 9
. . . . 7 . . . .
. . 3 4 . 2 8 . .
. . 1 . . 9 6 . .
. 8 . . 3 . . 7 .
. . 2 5 . . 4 . .
. . 5 6 . 1 3 . .
. . . . 8 . . . .
9 . . . . . . . 2 # Arabian Star from Claudia
# after SSTS
*-----------------------------------------------------------------------------*
| 4 -12567 *678 | 138 156 3568 |*1257 12356 9 |
| 12568 1256 689 | 1389 7 3568 | 125 123456 13456 |
| 1567 15679 3 | 4 1569 2 | 8 156 1567 |
|-------------------------+-------------------------+-------------------------|
| 357 3457 1 | 78 24 9 | 6 2358 358 |
| 56 8 469 | 12 3 46 | 1259 7 15 |
| 367 3679 2 | 5 16 #78 | 4 1389 138 |
|-------------------------+-------------------------+-------------------------|
| 278 247 5 | 6 29 1 | 3 489 478 |
|-12367 -123467 *467 | 29 8 *3457 |*1579 1456 -14567 |
| 9 -13467 *678 |+37 45 *3457 |*157 14568 2 |
*-----------------------------------------------------------------------------*
I'm not up on my finned fish, but the asterisk (*) cells seem to form a Swordfish in <7> with a quasi-fin (#). However, since the quasi-fin is not in a box with another member of the Swordfish, it appears that nothing can be derived using the standard definition of a finned fish. But, the relationship [r6c6]-7-[r4c4]=7=[r9c4] exists. This causes [r9c2]<>7 and reduces the Swordfish to an X-Wing. The final result is the same eliminations as the original Swordfish -- excluding [r9c4]. I called it a quasi-finned Swordfish in another posting. Does it have another name ... or an equivalent technique?
In a finned fish relationship, (I believe) one looks for an overlap to derive common eliminations. In a quasi-finned fish relationship, eliminations are prevented.