flip wrote:A type 4 UR destroys the unique rectangle
The validity of the Uniqueness Argument does not depend on your current solving state. Hence a "unique rectangle" cannot be destroyed.
flip wrote:A type 4 UR destroys the unique rectangle
eclark wrote:I can't even find ones that need type 2.
......................
can anyone give me one ?
..8|..5|...
...|23.|...
9.2|4..|...
---+---+---
.6.|...|...
..9|.4.|.57
8.3|.7.|.1.
---+---+---
3..|...|.7.
...|5..|.26
...|..8|4..
1467 1347 8 | 1679 169 5 | 12379 3469 1239
14567 147 14567 | 2 3 1679 | 1789 4689 189
9 137 2 | 4 8 167 | 1357 36 135
----------------------+----------------------+--------------------
*47 6 *47 | 1389 5 1239 | 2389 389 2389
12 12 9 | 368 4 36 | 368 5 7
8 5 3 | 69 7 269 | 269 1 4
----------------------+----------------------+--------------------
3 12489 1456 | 169 1269 4 | 1589 7 1589
*147 14789 *147 | 5 19 347 | 1389 2 6
12567 1279 1567 | 37 1269 8 | 4 39 1359
Sorry. it should read that a type 4 reduction destroys the unique rectangle (post edited).aeb wrote:flip wrote:A type 4 UR destroys the unique rectangle
The validity of the Uniqueness Argument does not depend on your current solving state. Hence a "unique rectangle" cannot be destroyed.
But a unique rectangle cannot be destroyed. Even when you solve a corner it still applies. Somewhere else I already pointed at http://homepages.cwi.nl/~aeb/games/sudoku/solving15.html - let me do it again. What is needed for the Local BUG Principle that this forum seems to be in the process of rediscovering is a collection of positions not fixed by having one of the original clues, and a collection of candidate values at those positions, two candidate values at each, where each row, column and box contains 0 or 2 candidates with any given value. Those candidates may be freely invented, they need not have any relation with the current list of candidates that some solver maintains. And the conclusion is that if the total number of solutions is odd, for example 1, then there is a solution and a position such that that solution there differs from both candidates at that position.flip wrote:Sorry. it should read that a type 4 reduction destroys the unique rectangle.aeb wrote:The validity of the Uniqueness Argument does not depend on your current solving state. Hence a "unique rectangle" cannot be destroyed.
aeb wrote:Somewhere else I already pointed at http://homepages.cwi.nl/~aeb/games/sudoku/solving15.html - let me do it again. What is needed for the Local BUG Principle that this forum seems to be in the process of rediscovering is a collection of positions not fixed by having one of the original clues, and a collection of candidate values at those positions, two candidate values at each, where each row, column and box contains 0 or 2 candidates with any given value. Those candidates may be freely invented, they need not have any relation with the current list of candidates that some solver maintains. And the conclusion is that if the total number of solutions is odd, for example 1, then there is a solution and a position such that that solution there differs from both candidates at that position.
Jeff wrote:aeb wrote:Somewhere else I already pointed at http://homepages.cwi.nl/~aeb/games/sudoku/solving15.html - let me do it again. What is needed for the Local BUG Principle that this forum seems to be in the process of rediscovering is a collection of positions not fixed by having one of the original clues, and a collection of candidate values at those positions, two candidate values at each, where each row, column and box contains 0 or 2 candidates with any given value. Those candidates may be freely invented, they need not have any relation with the current list of candidates that some solver maintains. And the conclusion is that if the total number of solutions is odd, for example 1, then there is a solution and a position such that that solution there differs from both candidates at that position.
Hi Aeb, I can understand the description of the local BUG principle in your web page. But, I have problem with the statements highlighted in the description above. Could you shed some more light on these statements? I suppose "position" means "cell" and "solution" means "true digit in a cell". Thanks in advance.
ronk wrote:eclark wrote:I can't even find ones that need type 2.
......................
can anyone give me one ?
If I understand the type definitions, a good example is #655 of the top1465.
- Code: Select all
..8|..5|...
...|23.|...
9.2|4..|...
---+---+---
.6.|...|...
..9|.4.|.57
8.3|.7.|.1.
---+---+---
3..|...|.7.
...|5..|.26
...|..8|4..
1467 1347 8 | 1679 169 5 | 12379 3469 1239
14567 147 14567 | 2 3 1679 | 1789 4689 189
9 137 2 | 4 8 167 | 1357 36 135
----------------------+----------------------+--------------------
*47 6 *47 | 1389 5 1239 | 2389 389 2389
12 12 9 | 368 4 36 | 368 5 7
8 5 3 | 69 7 269 | 269 1 4
----------------------+----------------------+--------------------
3 12489 1456 | 169 1269 4 | 1589 7 1589
*147 14789 *147 | 5 19 347 | 1389 2 6
12567 1279 1567 | 37 1269 8 | 4 39 1359
Eight 1s may be eliminated in box 7 and row 8.
Ron
Havard wrote:now give me a sudoku that requires type 3! (and can not be solved with 1,2 and 4 instead)
Hi Havard,
thanks for your explanations, together with MadOverlord's definitions i hope, i understood it now. Then this Angus' unlimited021 should be a "pure" type 3:
That puzzle is great! just what I wanted. Thank you!
# 1 2 2B 3 3B 4 4B
4 x
5 x
11 x
13 x
14 x
25 x
32 x x
39 x
41 x
45 x
52 x
56 x x
61 x
71 x x
82 x
91 x
92 x
94 x
Havard wrote:I don't know if you read the posts in reverse order or simply don't read them at all, but I saw Wolfang's post
flip wrote:Here are my solver results for UR with the top95.
The UR reductions are only attempted after all simpler reductions, and also after all xwing/swordfish/jellyfish, conjugate coloring, bug and xy-wing. No implication chains, tabling, nishio, T/E before the UR..