The New Sudoku Players' Forum

[Glenn100]

Code: Select all

*------------------------------------------------------------*
 | 12    78    9     | 1278  237   4     | 578z  6     3578s |
 | 4     6     78    | 5     379   789   | 1     2     378r  |
 | 12    3     5     | 6     127   178p  | 4     78q   9     |
 |-------------------+-------------------+-------------------|
 | 5     789   4     | 179   6     179   | 2     3     78    |
 | 6     789   78    | 3     4     2     | 789   5     1     |
 | 3     1     2     | 79    8     5     | 6     79    4     |
 |-------------------+-------------------+-------------------|
 | 7     4     3     | 289   259   6     | 589e  1     258z  |
 | 89    2     1     | 789   579   3     | 5789d 4     6     |
 | 89    5     6     | 4     1279  1789a | 3     789b  278c  |
 *-----------------------------------------------------------*

First ALS: a,b,c,d,e Five cells with six numbers 178925
Second ALS: p,q,r,s Four cells with five numbers 17835
The common restricted is (1) in p and a
The 5's in d and e point to the 5 in both z's
as does the 5 in s
What is wrong in what I have done? Neither of the 5's in the z's can be excluded. I thought I had this pretty well mastered...guess not.
Any and all help is appreciated.

[pjb]

All of the members of an ALS have to be in the same house, and this is not the case with either abcde or pqrs
Phil

[Glenn100]

Thanks Phil. I WILL remember this. I have spent several hours pondering about this puzzle but never gave consideration to the fact that they all had to be in the same house. I was under the impression that as long as each cell joined another cell in the ALS regardless of the house it was in, I was OK. Suprisingly, my way worked in almost all cases but, of course, it has to be the correct way 100% of the time. Glenn