JC, again you posted basically the same as my solution.
But i am not used to your notation. Please could you describe in words, how to read it ? I tried it below for mine.
- Code: Select all
*-------------------------------------------------------------------------*
| 568 1 4578 | 689 678 679 | 2 3 49 |
| 2 3-6 9 | 4 5 a36 | 78 78 1 |
| 38 37 478 | 12389 1378 12379 | 5 6 49 |
|-----------------------+-------------------------+-----------------------|
| 13689 4 128 | 13569 136 13569 | d369 e1259 7 |
| 1369 5 f17 | 1369 2 47 | d3469 e149 8 |
| 1369 f367 127 | 13569 47 8 | d3469 e12459 e235 |
|-----------------------+-------------------------+-----------------------|
| 7 289 3 | 2568 468 2456 | 1 24589 25 |
| 4 289 6 | 12358 138 1235 | 3789 25789 235 |
| 15 28 15 | 7 9 b234 | c348 248 6 |
*-------------------------------------------------------------------------*
(6=3)r2c6-r9c6=r9c7-(3=469)r456c7-(4|6|9)b6p2589=13b6p59.28-(1|3=6)b4p68 => -6r2c2, stte
if r2c6 is not 6, then it is 3,
then no 3 in r9c6, must be in r9c7,
then no 3, but 469 in r456c7,
then in the rest of box 6, marked e, only candidates 1235 are left and r6c9 must be 3 (only cell) and r5c8 must be 1 (only candidate).
[Rem.: the 3 is trivial and the 1 immediately pops up with the triple 469, which leaves 1 in r5c8.]
then no 1 in r5c3, must be 7, and no 3 in r6c2, must be 6.