The New Sudoku Players' Forum

[ArkieTech]

Code: Select all

 *-----------*
 |25.|...|...|
 |...|...|74.|
 |7..|.91|...|
 |---+---+---|
 |8..|1..|3..|
 |.4.|2.5|.1.|
 |..2|..3|..7|
 |---+---+---|
 |...|64.|..8|
 |.96|...|...|
 |...|...|.56|
 *-----------*


[pjb]

Code: Select all

2      5      48     | 47     3      467    | 69     89     1     
19     36     19     | 58     25     268    | 7      4     a35     
7      36    c48     |d45     9      1      | 256   b38     235   
---------------------+----------------------+---------------------
8      7      59     | 1      6      49     | 3      2      45     
6      4      3      | 2      7      5      | 8      1      9     
59     1      2      | 49     8      3      | 45     6      7     
---------------------+----------------------+---------------------
135    2      157    | 6      4      79     | 19     379    8     
134    9      6      | 3578   125    278    | 124    37     234   
134    8      17     | 379    12     279    | 1249   5      6

XY chain:

(5=3)r2c9 - (3=8)r3c8 - (8=4)r3c3 - (4=5)r3c4; => r2c45, r3c79 <> 5, stte

(alternatively: (5=3)r2c9 - (3=458)r3c348)

Phil

[7b53]

first time participating, don't know how to write the notation.
so just say in words...

either r78c8=37 or r2c9=3 resulting r3c8, r8c9<>3

[Leren]

Code: Select all

*--------------------------------------------------------------*
| 2     5     48     | 47    3     467    | 69    89    1      |
| 19   b36    19     | 58    25    268    | 7     4    a35     |
| 7    c36    48     | 45    9     1      |d26-5  38    235    |
|--------------------+--------------------+--------------------|
| 8     7     59     | 1     6     49     | 3     2     45     |
| 6     4     3      | 2     7     5      | 8     1     9      |
| 59    1     2      | 49    8     3      | 45    6     7      |
|--------------------+--------------------+--------------------|
| 135   2     157    | 6     4     79     | 19    379   8      |
| 134   9     6      | 3578  125   278    | 124   37    234    |
| 134   8     17     | 379   12    279    | 1249  5     6      |
*--------------------------------------------------------------*

h-wing: (5=3) r2c9 - (3=6) r2c2 - r3c2 = r3c7 => r3c7 <> 5; stte

Leren

[tlanglet]

(6=3)r3c2-(3=8)r3c8-(89=96)r1c87 => r3c7<>6

Ted

[Marty R.]

Code: Select all

2      5      48     | 47     3      467    | 69     89     1     
19     36     19     | 58     25     268    | 7      4      a35     
7      36     c48    | d45    9      1      | 256    b38    235   
---------------------+----------------------+---------------------
8      7      59     | 1      6      49     | 3      2      45     
6      4      3      | 2      7      5      | 8      1      9     
59     1      2      | 49     8      3      | 45     6      7     
---------------------+----------------------+---------------------
135    2      157    | 6      4      79     | 19     379    8     
134    9      6      | 3578   125    278    | 124    37     234   
134    8      17     | 379    12     279    | 1249   5      6

XY chain:

(5=3)r2c9 - (3=8)r3c8 - (8=4)r3c3 - (4=5)r3c4; => r2c45, r3c79 <> 5, stte

(alternatively: (5=3)r2c9 - (458=3)r3c348)

Phil

Same XY-Chain.

[7b53]

Code: Select all

*--------------------------------------------------------------*
| 2     5     48     | 47    3     467    | 69    89    1      |
| 19   b36    19     | 58    25    268    | 7     4    a35     |
| 7    c36    48     | 45    9     1      |d26-5  38    235    |
|--------------------+--------------------+--------------------|
| 8     7     59     | 1     6     49     | 3     2     45     |
| 6     4     3      | 2     7     5      | 8     1     9      |
| 59    1     2      | 49    8     3      | 45    6     7      |
|--------------------+--------------------+--------------------|
| 135   2     157    | 6     4     79     | 19    379   8      |
| 134   9     6      | 3578  125   278    | 124   37    234    |
| 134   8     17     | 379   12    279    | 1249  5     6      |
*--------------------------------------------------------------*

we can also say...
either r789c7=124 or r4c9=4 => r6c7, r8c9<>4
wondering how the notation should be written ? thanks

[daj95376]

we can also say...
either r789c7=124 or r4c9=4 => r6c7, r8c9<>4
wondering how the notation should be written ? thanks

Since you failed to provide any indication of your logic, there's nothing to notate. However, here's one possible way to derive your results.

Code: Select all

 +--------------------------------------------------------------+
 |  2     5     48    |  47    3     467   |  69    89    1     |
 |  19    36    19    |  58    25    268   |  7     4     35    |
 |  7     36    48    |  45    9     1     |  256   38    235   |
 |--------------------+--------------------+--------------------|
 |  8     7     59    |  1     6     49    |  3     2     45    |
 |  6     4     3     |  2     7     5     |  8     1     9     |
 |  59    1     2     |  49    8     3     |  45    6     7     |
 |--------------------+--------------------+--------------------|
 |  135   2     157   |  6     4     79    |  19    379   8     |
 |  134   9     6     |  3578  125   278   |  124   37    234   |
 |  134   8     17    |  379   12    279   |  1249  5     6     |
 +--------------------------------------------------------------+
 # 61 eliminations remain

 (124=9)r789c7 - (9=6)r1c7 - r1c6 = r2c6 - (6=3)r2c2 - (3=5)r2c9 - (5=4)r4c9  =>  r8c9<>4


Or the ALS can be dropped and your result replaced with this chain:

Code: Select all

 (4=5)r4c9 - r2c9 = r2c45 - (5=4)r3c4 - (4=8)r3c3 - (8=3)r3c8 - r23c9 = (3)r8c9  =>  r8c9<>4


This is the first and last time that I'll fill in the blanks.

[7b53]

everyone write these notations kind of differently. that was the reason I asked.
which is the standard way ? or perhaps there is no standard way.
yours is nice and clear.

thank you ; daj

[daj95376]

everyone write these notations kind of differently. that was the reason I asked.
which is the standard way ? or perhaps there is no standard way.
yours is nice and clear.

To me, the "notation standard" has evaporated into the cloud. Everyone likes to be cute and do whatever is necessary to bastardize the notation so they can compress their statements to where they're as compact as possible. This often involves creating an ALS expression instead of two or more simpler expressions -- especially when combining multiple bivalue cells in a house/unit. I expect to see any day now where an XY-Chain will be expressed as (X=X)list_of_cells. In fact, I may do it myself!

[Marty R.]

everyone write these notations kind of differently. that was the reason I asked.
which is the standard way ? or perhaps there is no standard way.
yours is nice and clear.

To me, the "notation standard" has evaporated into the cloud. Everyone likes to be cute and do whatever is necessary to bastardize the notation so they can compress their statements to where they're as compact as possible. This often involves creating an ALS expression instead of two or more simpler expressions -- especially when combining multiple bivalue cells in a house/unit. I expect to see any day now where an XY-Chain will be expressed as (X=X)list_of_cells. In fact, I may do it myself!

As a notation newcomer, I tend to agree, even if I might be guilty of some of the bastardization to which you refer. Just when I think I've learned something, someone does it differently and I have to learn it again.