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[ArkieTech]

Code: Select all

 *-----------*
 |.5.|.3.|...|
 |6.4|9.2|...|
 |.7.|.4.|...|
 |---+---+---|
 |.9.|...|.5.|
 |1.5|...|2.4|
 |.8.|...|.7.|
 |---+---+---|
 |...|.2.|.1.|
 |...|7.6|8.9|
 |...|.9.|.6.|
 *-----------*


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[pjb]

Code: Select all

289    5      1289   | 168    3      178    | 14679  2489   12678 
6      13     4      | 9      1578   2      | 1357   38     13578 
2389   7      12389  | 1568   4      158    | 13569  2389   123568
---------------------+----------------------+---------------------
2347   9      2367   | 12348  168    1348   | 136    5      1368   
1      36     5      | 38     678    3789   | 2      389    4     
234    8      236    | 12345  156    13459  | 1369   7      136   
---------------------+----------------------+---------------------
5789   46     6789   | 3458   2      3458   | 3457   1      357   
35     24     13     | 7      15     6      | 8      24     9     
578    124    178    | 13458  9      13458  | 3457   6      2357   


After basic moves, a one step solution for this one is the ALS XZ:
A: r5c24; B: r468c5; X value 8; Z value 6; => -6r5c5; stte

[Leren]

A simple 1 stepper is a W Wing 38 r2c8, r5c4 linked by 3's in r25c2 => r5c8 <8>

stte except for 1 hidden double/naked triple in column 5

Leren

[tlanglet]

I also found the w-wing (38)..........

[Marty R.]

I also saw the W-Wing on 38 and screwed up on some basics, because I didn't see the finish line. The same W-Wing is connected by 8s in c5 so a 3 can also be eliminated from r5c8.

[David P Bird]

There is this continuous loop:

(3=8)r5c4 - (8)r45c5 = (8)r2c5 - (8=3)r2c8 - (3)r2c1 = (3)r5c2 - Loop
=> r4c4,r456c6 <> 8, r2c9 <> 8, r2c79 <> 3, r5c68 <> 3
But it doesn't collapse the puzzle

pjb's approach produces this very neat AIC:

(6=3)r5c2 - (3=8)r5c4 - (158=6)ANS:r468c5 => r5c5 <> 6

My more plodding approach navigated column 5 differently to make the same elimination:

(6=3)r5c2 - (3=8)r5c4 - (8)r45c5 = (8-7)r2c5 = (7)r5c5 => r5c5 <> 6