With help of yzfwsf's solver (presented the way I understand the pattern)
- Code: Select all
+--------------------------+------------------------------+--------------------------+
| 9 8 B135 | 7 1245 145 | 6 124 134 |
| 7 1236 B136 | 468 9 1468 | 5 1248 134 |
| 1256 1256 4 | <568 <12568 3 | T12789 T1289 T179 | CL1
+--------------------------+------------------------------+--------------------------+
| 4 T1356 13568 | <3568 <3568 9 | <138 7 2 |
| 1568 9 13568 | 2 345678 45678 | 1348 14568 146 |
| 568 7 2 | 1 34568 4568 | 3489 45689 469 |
+--------------------------+------------------------------+--------------------------+
| 3 <126 16789 | 4689 14678 14678 | 12479 12469 5 |
| <156 4 15679 | <569 <1567 2 | <179 3 8 | CL2
| 12568 <1256 156789 | 345689 1345678 145678 | 12479 12469 14679 |
+--------------------------+------------------------------+--------------------------+
CL3 CH 56 CH 156 CH 1
b7 CH 156
Senior exocet (1356)r12c3, r4c2, r3c789 (three cells with two locked digits as object cells)
"Cross-lines" are rows 3, 8 and column 2 (unsolved S-cells tagged with '<')
+3r12c3 => +3r4c2 (no count of cover houses for digit 3)
Cover-houses for digit 1: c57, b7; for digits 5, 6: c45, b7.
Eliminations from the pattern: -28 r3c78 (not locked, non base digits in target cells) => basics to the end.
Note 2: another choice for S-cells and CL/CH: r56c1 instead of r79c2, b4 as CL, c1 as CH.
In such case, I agree with SpAce, "cross-line" is not the right name...