The New Sudoku Players' Forum

[ArkieTech]

Code: Select all

 *-----------*
 |..6|34.|7..|
 |9..|8..|.24|
 |...|...|...|
 |---+---+---|
 |.4.|...|6..|
 |39.|.8.|.41|
 |..5|...|.9.|
 |---+---+---|
 |...|...|...|
 |86.|..3|..2|
 |..4|.51|3..|
 *-----------*


Play/Print this puzzle online

[Leren]

Code: Select all

*-----------------------------------------------------------------------*
| 125    1258   6       | 3      4      259     | 7      158   b589     |
| 9      1357   137     | 8      167    567     | 15     2      4       |
| 4      12578  1278    | 12579  1279   2579    |c1589   36     36      |
|-----------------------+-----------------------+-----------------------|
| 127    4      1278    | 12579  12379  2579    | 6      3578  a3578    |
| 3      9      27      | 2567   8      2567    |e2-5    4      1       |
| 6      1278   5       | 127    1237   4       |d28     9      378     |
|-----------------------+-----------------------+-----------------------|
| 15     135    139     | 24679  2679   8       | 149    167    679     |
| 8      6      19      | 479    79     3       | 1459   157    2       |
| 27     27     4       | 69     5      1       | 3      68     689     |
*-----------------------------------------------------------------------*

(5) r4c9 = (5-9) r1c9 = (9-8) r3c7 = (8-2) r6c7 = (2) r5c7 => - 5 r5c7; stte

Leren

[SteveG48]

Code: Select all

 *---------------------------------------------------------------------*
 | 125    1258   6      | 3      4      259    |  7     c158    589    |
 | 9      1357   137    | 8      167    567    | b15     2      4      |
 | 4      12578  1278   | 12579  1279   2579   | b1589   36     36     |
 *----------------------+----------------------+-----------------------|
 | 127    4      1278   | 12579  12379  2579   |  6      3578   3578   |
 | 3      9      27     | 2567   8      2567   | a2-5    4      1      |
 | 6      1278   5      | 127    1237   4      |  28     9      378    |
 *----------------------+----------------------+-----------------------|
 | 15     135    139    | 24679  2679   8      | b149    167    679    |
 | 8      6      19     | 479    79     3      |be1459  d157    2      |
 | 27     27     4      | 69     5      1      |  3      68     689    |
 *---------------------------------------------------------------------*


(2=5)r5c7 - (5=1489)r2378c7 - (18=5)r1c8 - r8c8 = 5r8c7 => -5 r5c7 ; stte

[pjb]

Code: Select all

 125     1258    6      | 3      4      259    | 7      158   b589   
 9       1357    137    | 8      167    567    | 15     2      4     
 4       12578   1278   | 12579  1279   2579   |c1589   36     36     
------------------------+----------------------+---------------------
 127     4       1278   | 1279-5 12379  279-5  | 6     f3578  a3578   
 3       9       27     | 2567   8      2567   |e2-5    4      1     
 6       1278    5      | 127    1237   4      |d28     9      378   
------------------------+----------------------+---------------------
 15      135     139    | 24679  2679   8      | 149    167    679   
 8       6       19     | 479    79     3      | 1459   157    2     
 27      27      4      | 69     5      1      | 3      68     689   


(5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 = r4c8 => -5 r4c46, r5c7; stte

Phil

[Leren]

pjb wrote : (5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 = r4c8 => -5 r4c46, r5c7; stte

This looks like one for notation enthusiasts. It's the same chain as mine except for the last term where you have to "remember" the initial assumption as well as applying the previous term. Perhaps a more complete notation would be something like:

*(5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 *= r4c8 => -5 r4c46, r5c7; or

(5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 = r4c8 => -5 r4c46, r5c7;
\---------------------------------------------------------------/

Leren

[SteveG48]

pjb wrote : (5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 = r4c8 => -5 r4c46, r5c7; stte

This looks like one for notation enthusiasts. It's the same chain as mine except for the last term where you have to "remember" the initial assumption as well as applying the previous term. Perhaps a more complete notation would be something like:

*(5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 *= r4c8 => -5 r4c46, r5c7; or

(5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 = r4c8 => -5 r4c46, r5c7;
\---------------------------------------------------------------/

Leren

How about if we simply write Phil's as:

(5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 = r4c89 => -5 r4c46, r5c7; stte

Then no memory is required.

[Leren]

Steve48 Wrote : How about if we simply write Phil's as: (5)r4c9 = (5-9)r1c9 = (9-8)r3c7 = (8-2)r6c7 = (2-5)r5c7 = r4c89 => -5 r4c46, r5c7; stte Then no memory is required.

Nice one - works for me.

Leren

[pjb]

Thanks guys. Point taken. When I posted there were no replies yet. If I had seen your solution, Leren, I would have gone looking for something else.
Cheers, Phil