Next Suggested Move and Why

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Next Suggested Move and Why

Postby al_bell » Wed Apr 16, 2008 8:41 pm

Code: Select all

Without Pencil Marks

. . 9 | . . 8 | . . .
. . . | . 3 . | . 4 .
. . 7 | . . . | . . 5
------+-------+------
. . 8 | . . . | 9 . .
3 . . | . 4 . | . . 2
. . 6 | . . . | 7 . .
------+-------+------
2 . . | . . . | 5 . .
. 1 . | . 5 . | . . .
. . . | 6 . . | 8 . .


With Pencil Marks

145 345   9 |   1245  12     8 | 23   67   67
568 568   2 |    579   3   579 |  1    4   89
148 348   7 |    124  69   126 | 23   89    5
------------+------------------+--------------
457 245   8 |   1235  67 12356 |  9  135  134
  3  79   1 |    589   4   579 |  6   58    2
459 245   6 | 123589  89 12359 |  7  135 1348
------------+------------------+--------------
  2  68   4 |  13789 789  1379 |  5 1679 1679
 68   1   3 |    289   5   279 |  4 2679  679
 79  79   5 |      6  12     4 |  8  123   13



I am wondering what the next step should be and why.

thank you
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Postby ArkieTech » Wed Apr 16, 2008 9:27 pm

Code: Select all
.------------------------.------------------------.------------------------.
| 145     345     9      | 1245    12      8      | 23      67      67     |
| 568     568     2      | 579     3       579    | 1       4       89     |
| 148     348     7      | 124    A69      126    | 23      89      5      |
:------------------------+------------------------+------------------------:
| 457     245     8      | 1235   A67      12356  | 9       135     134    |
| 3       79      1      |B589     4      B579    | 6      B58      2      |
| 459     245     6      | 123589  8-9     12359  | 7       135     1348   |
:------------------------+------------------------+------------------------:
| 2       68      4      | 13789   789     1379   | 5       1679    1679   |
| 68      1       3      | 289     5       279    | 4       2679    679    |
| 79      79      5      | 6       12      4      | 8       123     13     |
'------------------------'------------------------'------------------------'
ALS:A(679)B(5789)C(7)=>r6c5<>9
later ur(67)=>r7c8=1


dan
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Postby storm_norm » Thu Apr 17, 2008 12:23 am

Code: Select all
145    345    9      | 1245   12     8      | 23     67     67
568    568    2      | 579    3      5679   | 1      4      89
1468   3468   7      | 1249   6(9)   1269   | 23    #89     5
------------------------------------------------------------------
457    2457   8      | 12357  67     123567 | 9      135    134
3      579    1      |#5789   4      579    | 6     #58     2
459    2459   6      | 123589 89#    12359  | 7      1358   1348
------------------------------------------------------------------
2      68     4      | 13789  789    1379   | 5      1679   1679
68     1      3      | 2789   5      279    | 4      2679   679
79     79     5      | 6      12     4      | 8      123    13


the # marked in the grid is a W-wing on {8,9}...
the pair {8,9} can see the strong link on 8's in row 5 and the associated 9's see the 9 in r3c5.
that solves r3c5 as 6 directly.


leaves you with this...

Code: Select all
14     34     9      | 5      12     8      | 23    #67    #67
56     56     2      | 7      3      9      | 1      4      89
18     38     7      | 4      6      12     | 23     9      5
------------------------------------------------------------------
45     245    8      | 123    7      6      | 9      135    134
3      579    1      | 5789   4      579    | 6      8      2
9      245    6      | 123    8      123    | 7      135    134
------------------------------------------------------------------
2      68     4      | 138    9      137    | 5     #1(67) #67
68     1      3      | 28     5      27     | 4      267    9
79     79     5      | 6      12     4      | 8      123    13


the cells marked # is a type 1 UR on {6,7} and removes {6,7} from r7c8 and solves r7c8 as 1 and solves the puzzle.
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Postby tarek » Thu Apr 17, 2008 6:04 pm

ArkieTech wrote:
Code: Select all
.------------------------.------------------------.------------------------.
| 145     345     9      | 1245    12      8      | 23      67      67     |
| 568     568     2      | 579     3       579    | 1       4       89     |
| 148     348     7      | 124    A69      126    | 23      89      5      |
:------------------------+------------------------+------------------------:
| 457     245     8      | 1235   A67      12356  | 9       135     134    |
| 3       79      1      |B589     4      B579    | 6      B58      2      |
| 459     245     6      | 123589  8-9     12359  | 7       135     1348   |
:------------------------+------------------------+------------------------:
| 2       68      4      | 13789   789     1379   | 5       1679    1679   |
| 68      1       3      | 289     5       279    | 4       2679    679    |
| 79      79      5      | 6       12      4      | 8       123     13     |
'------------------------'------------------------'------------------------'
ALS:A(679)B(5789)C(7)=>r6c5<>9
later ur(67)=>r7c8=1


dan
Isn't r5c2 part of you B set ???

I couldn't spot it myself. My solver says 2 ALS-XY, doubles & UR-1

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Postby ArkieTech » Thu Apr 17, 2008 7:14 pm

Isn't r5c2 part of you B set ???


Wouldn't that take the "Almost" out of it -- making 4 candidates for 4 cells?
I look for 4 candidates to go into 3 cells with a common. I am new at this and just learning....Help!

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Postby hobiwan » Thu Apr 17, 2008 7:34 pm

ArkieTech wrote:Wouldn't that take the "Almost" out of it -- making 4 candidates for 4 cells?
I look for 4 candidates to go into 3 cells with a common. I am new at this and just learning....Help!

dan

As far as I can see your ALS-XZ is perfectly valid.
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Postby tarek » Thu Apr 17, 2008 8:00 pm

hobiwan wrote:
ArkieTech wrote:Wouldn't that take the "Almost" out of it -- making 4 candidates for 4 cells?
I look for 4 candidates to go into 3 cells with a common. I am new at this and just learning....Help!

dan

As far as I can see your ALS-XZ is perfectly valid.
Absolutely, I was confused when looking at the C(7) & thought it was an ALS-XY.

This is the last time that I will try replying while thinking about something else:)

Good one ArkieTech

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Postby ttt » Sat Apr 19, 2008 3:58 pm

Code: Select all
I am wondering what the next step should be and why.


Based on Arkie Tech meant that :
1- If r5c468=(triple 589) => r6c6<>9
2- If r5c468<>(triple 589) => r5c6=7 => r4c5=6 => r3c5=9 => r6c6<>9
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Postby ArkieTech » Sat Apr 19, 2008 4:06 pm

ttt said:
1- If r5c468=(triple 589) => r6c6<>9
2- If r5c468<>(triple 589) => r5c6=7 => r4c5=6 => r3c5=9 => r6c6<>9


Excellent! I like it.

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Postby wintder » Sat Apr 19, 2008 5:34 pm

storm_norm wrote:the # marked in the grid is a W-wing on {8,9}...
the pair {8,9} can see the strong link on 8's in row 5 and the associated 9's see the 9 in r3c5.
that solves r3c5 as 6 directly.


storm_norm, I like this route.
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Postby daj95376 » Sat Apr 19, 2008 7:03 pm

ttt wrote:Based on Arkie Tech:

1- If r5c468=589 => r5c2=7 => r6c1=9 => r6c5<>9
2- If r5c468<>589 => r5c6=7 => r4c5=6 => r3c5=9 => r6c5<>9

I like it too. It reminds me of the (old-style?) double implication chain where [r5c2]=7 or [r5c6]=7.
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Postby storm_norm » Sun Apr 20, 2008 6:53 pm

wintder wrote:
storm_norm wrote:the # marked in the grid is a W-wing on {8,9}...
the pair {8,9} can see the strong link on 8's in row 5 and the associated 9's see the 9 in r3c5.
that solves r3c5 as 6 directly.


storm_norm, I like this route.


thank you, me too.
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