Next move

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Next move

Postby BakyX » Sun Dec 21, 2014 1:41 am

Hi again. Has this puzzle exactly one solution ? If yes, how to solve that ?

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Re: Next move

Postby JasonLion » Sun Dec 21, 2014 4:18 am

Yes, that is a valid puzzle.

One possible solution is a finned X-Wing on 1, and then singles to the end.
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Re: Next move

Postby Leren » Sun Dec 21, 2014 9:27 am

Code: Select all
*--------------------------------------------------------------*
| 23459 23489 4578   | 6     789   2347   | 249   1     478    |
| 249   2489  6      | 147   1789  1247   | 5     3     478    |
| 2349  1     478    | 347   789   5      | 249   278   6      |
|--------------------+--------------------+--------------------|
| 7     34    45     | 345   2     9      | 8     6     1      |
| 1359  3689 a158    | 135   16    3-1    | 7     4     2      |
| 14    46    2      | 8     167   147    | 3     9     5      |
|--------------------+--------------------+--------------------|
| 6     7    b14     | 12    3     8      | 124   5     9      |
| 8     5     9      | 127   4     6      | 12    27    3      |
|c124   24    3      | 9     5    d17     | 6     78    478    |
*--------------------------------------------------------------*

Another solution is a 2 Stringed Kite : (1) r5c3 = r7c3 - r9c1 = (1) r9c6 => - 1 r5c6; stte

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Last edited by Leren on Tue Dec 23, 2014 7:40 pm, edited 1 time in total.
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Re: Next move

Postby BakyX » Tue Dec 23, 2014 5:39 pm

JasonLion: Thank you. I'm still not enough good at finding finned X-wings.

Leren: Thank you too. I think I understand what do you mean. We've got string "abcd" and now a=1 or d=1. But I don't understand your notation:
2 Stringed Kite : (1) r5c3 - r7c3 = r9c1 = (1) r9c6 => - 1 r5c6; stte
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Re: Next move

Postby Leren » Tue Dec 23, 2014 7:52 pm

There were typos in my notation, which I've now corrected to: (1) r5c3 = r7c3 - r9c1 = (1) r9c6

What this means in words, when read from left to right, is : If r5c3 is not 1, then r7c3 is 1, so r9c1 is not 1, so r9c6 is 1

When read from right to left it says : if r9c6 is not 1, then r9c1 is 1, so r7c3 is not 1, so r5c3 is 1.

Note that the 1's are placed in brackets to indicate that whether they are assumed to be True or False depends on which direction you are reading the chain.

Also, the second and third terms do not include 1's. it's customary to only include the number when it changes from the previous term, which de-clutters the notation a bit.

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Re: Next move

Postby BakyX » Sun Dec 28, 2014 11:50 am

Thank you, Leren :)
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