I am a newbie, I just know Sudoku over two months ago. I always come Sudoku.com.au site to solve puzzle every evening 10-11pm after hard working day. At present a lot techniques to solve Sudoku, but I can’t study or understand all (not much time and my English not enough). After I solved puzzle I try to look for rule of numbers on solution then I saw PAIRS – for me that is NEW TECHNIQUE, I don’t know this technique ready or not. I post here and if this technicque ready please show me.
a1 a2 a3 a456,789 a456,789 a456,789 a456,789 a456,789 a456,789
a4 a5 a6 a123,789 a123,789 a123,789 a123,789 a123,789 a123,789
a7 a8 a9 a123,456 a123,456 a123,456 a123,456 a123,456 a123,456
T-1 : Always have at lest 03 pair of numbers in 3 block on the same row or column.
Example :
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a1 a2 a3 a7 a9 a4 a6
a4 a5 a6 a1 a3 a2 a7 a9
a7 a8 a9 a2 a4 a6 a3 a1
Easy to demonstrate this rule : if a1 & a2 not the same row in block 2&3 then a3 has to the same row with a1 or a2 in block 2&3, continue for row 2&3 => T1
Wow… too simple, but I think sometimes it’s useful to solve puzzle. Can extend this rule more? Maybe, but I am not much time, smart or tool (progamme…) to do this.
Exampe (puzzle from Sudoku.com.au Nov. 10-2006 – tough)
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8 0 0 0 4 0 0 0 0
0 9 5 0 0 3 0 0 0
0 0 0 2 0 0 0 0 6
6 0 0 0 0 0 2 0 0
0 2 0 7 0 1 0 4 0
0 0 3 0 0 0 0 0 9
7 0 0 0 0 9 0 0 0
0 0 0 5 0 0 6 8 0
0 0 0 0 2 0 0 0 1
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8 1367 1267 19 4 75 13579 123579 2357
124 9 5 6 178 3 1478 127 2478
134 1347 147 2 15789 578 1345789 13579 6
39 39 458
7 6 1
48 58 2
13 138 9
5 137 47
3 2 6
1- On column 6 – block 8 : Based on T-1 (67), (64) impossible => (69), (94), (97)
2- On column 4 – block 2 : Based on T-1 (61), (62) impossible => (21), (69)
Pair (69) => r1c4=9 , r4c4=3, r4c5=9 , r7c4=1 => based on T-1 : on column 4 in block 8 only pair (15) => r4c6=5, r3c5=5, r2c5=1, r1c6=7, r6c5=8, r6c4=4, r8c6=4, r8c5=7 => impossibe
Thus, only pair (12) => r1c4=1, r3c5=9 … solved by some chains more.
My English is too bad, someone can edit and extend this technicque if possible
TTT
