pjb wrote:(5=9)r4c2 - r5c1(r4c6) = r8c1 - r8c6 = (9-4)r2c6 = r1c6 - (4=5)r1c8 => -5 r1c2; stte
Please mark, where you use remembered digits (making the chain unidirectional), otherwise the link 9r8c6=r2c6 just looks wrong.
- Code: Select all
+--------------------+-------------------+-------------------+
| 3 7-5 9 | 6 578 e458 | 1 e45 2 |
| 8 6 2 | 1 59 459 | 7 459 3 |
| a57 4 1 | 379 3579 2 | 8 59 6 |
+--------------------+-------------------+-------------------+
| 6 c59 7 | 4 2 d39 | 359 8 1 |
| b59 1 3 | 78 678 68 | 4 2 59 |
| 4 2 8 | 5 39 1 | 39 6 7 |
+--------------------+-------------------+-------------------+
| 1 379 4 | 39 56 56 | 2 37 8 |
| c79 3789 5 | 2 1 d389 | 6 37 4 |
| 2 38 6 | 38 4 7 | 59 1 59 |
+-------------------+-------------------+-------------------+
5r3c1 = (5-9)r5c1 = 9r4c2 & r8c1 - (9=38)r48c6 - (8=45)r1c68 => -5r1c2, stte