Hi, i have discovered SUDOKU puzzles yesterday and i'm addict.
I think the technic is easy
a Block-MAtrix 3*3 of MAtrix 3*3, my initial error was to try to solve like a computer, also with sets , remainig number of rows and columns and then intersection, that can be done but u can mistake very easy!
My technic (probably technic of many people more!!!) is the next:
a block column can just three 7s i.e.
A11 A12 A13
* * * | 7 * * | * * *
7 * * | * * * | * * *
* * * | * * * | * * 7
-------------------
* * * | * * * | * 7 *
* * * | * * 7 | * * *
* 7 * | * * * | * * *
-------------------
* * 7 | * * * | * * *
* * * | * 7 * | * * *
* * * | * * * |7 * *
A31 A32 A33
The goal is a heuristical methode to prove remaining numbers attending to block-matrix intersecion.
Also
Ci matrix vector column for i=1..3
(A11)
C1 = (A21)
(A31)
Rj matrix vector row for j=1 ..3
(A31)
R1 = (A32)
(A33)
And last inspect inconsistences in each Aij
I have done several sudoku Puzzles , with this technic in times under 8/9 minutes and i'm a newbie!!!
Another technic is
intersecion(remaining(column[i], remaining(row[j]), Aij) but i think, it's faster the other!!!
