find this situation:
- Code: Select all
123 . . |123 . . |123 . .
123 . . |123 . . |123 . .
123 . . |123 . . |1234 . .
--------+--------+---------
. . . | . . . | . . .
. . . | . . . | . . .
. . . | . . . | . . .
--------+--------+---------
. . . | . . . | . . .
. . . | . . . | . . .
. . . | . . . | . . .
You could apply a variation of the usual uniqueness logic here.
Assume 4 is not the final value of r3c7. Then, in a solution to the puzzle,
each of the cells c1r1-3, c4r1-3, and c7r1-3 will contain a 1, 2 or 3.
After finding a solution, in those 9 cells you could change
each 1 to a 2, each 2 to a 3, and each 3 to a 1, and
you'd have a second solution. But this contradicts
the assumption that the puzzle is valid. So the
assumption that 4 is not the final value of r3c7
must be wrong.
So, you could enter 4 as the final value
for that cell, and then continue solving the puzzle.
The trouble is, I can't seem to create a puzzle with
a unique solution that has the candidate configuration
pictured above.
So, I thought I'd ask the forum: can anyone come up with such a puzzle?
Or one in which there is a different "uniqueness pattern"
in which each cell in the pattern has at least 3 candidates?
Thanks in advance,
Nick
P.S. I got the idea for the puzzle above directly from posts by tso
and Myth Jellies. (So ... not really that much creative thinking
on my part!)