JPF wrote:How do you get 78 bits ?
Starting from the locked pattern, first placing digit 1 as in udosuks example:
- Code: Select all
123|4--|...
456|...|...
789|...|4..
---+---+---
|4.|...|...
|..|...|.4.
|..|..4|...
---+---+---
..4|...|...
...|.4.|...
...|...|..4
In box 4, 5 options=3 bits, box 2, 6 options=3 bits. Then boxes 6 and 8, also 3 bits each, finally box 9 requires only 2 bits. That's 14 bits for digit 1.
- Code: Select all
123|4..|...
456|...|...
789|-1-|4..
---+---+---
|4.|...|...
|.1|...|.4.
|..|..4|..1
---+---+---
..4|...|.1.
...|14.|...
...|...|..4
Next, go for digit 7. Max 4 possibilities in box 4 = 2 bits, the other boxes as digit 1, total of 13 bits for digit 7.
- Code: Select all
123|4.7|...
456|...|...
789|.1.|4..
---+---+---
.4.|...|7..
.71|...|.4.
...|..4|..1
---+---+---
..4|.7.|.1.
...|14.|..7
...|...|..4
Next, digit 8, max 4 options in box 2, otherwise as digit 1 => 13 bits. Digit 9 is done in the same way, 13 bits.
- Code: Select all
123|4.7|...
456|98.|...
789|.1.|4..
---+---+---
84.|...|7..
.71|...|.49
9..|..4|8.1
---+---+---
..4|.7.|.18
...|14.|.97
...|8.9|..4
From now on there can be max 4 possibilities for any digit, the next two digits can be solved in 5*2bits each.
After that there's max 2 possibilities left, the 8th digit can be solved in 5 bits, and the last one comes for free. That's 14+3*13+2*10+5=78 bits.
This should work on any grid, and all grids can be done in the same order to get the same 78 bit format. If we instead start with box 1 + all digits 1 locked and then proceed in numerical order, we would reach 80bits/grid.
RW