## Method for another Challenger sudoku

Post the puzzle or solving technique that's causing you trouble and someone will help

### Method for another Challenger sudoku

I reviewed these numbers many times I hope I am not missing a simple clue.
So the original game is:
Code: Select all
`. 1 .|2 . .|5 . .5 . 2|. . 8|3 . .. 8 .|. 5 .|. 6 1-----------------3 . 8|. 4 .|. . .. . .|5 . 2|. . .. . .|. 8 .|1 . 9------------------4 2 .|. 6 .|. 7 .. . 5|7 . .|6 . 3. . 7|. . 5|. 1 .`

And what I have so far is:
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`79    1     346  |2     379   34679|5     489   4785     46    2    |1469  179   8    |3     49    4779    8     34   |349   5     3479 |2     6     1-----------------------------------------------------3     56    8    |169   4     169  |7     25    261     467   9    |5     37    2    |48    348   4682     4567  46   |36    8     367  |1     345   9-----------------------------------------------------4     2     1    |389   6     39   |89    7     58     9     5    |7     12    14   |6     24    36     3     7    |489   29    5    |489   1     248`

Finding the (7,9) pair at B1 only helped to cross out a 7 at r2c2, but that was it. So ideas please?
Thanks.
JeJ

Posts: 76
Joined: 06 January 2011

### Re: Method for another Challenger sudoku

Think about R4 and B4 and see if you can find what is hidden.

JasonLion
2017 Supporter

Posts: 640
Joined: 25 October 2007
Location: Silver Spring, MD, USA

### Re: Method for another Challenger sudoku

JasonLion wrote:Think about R4 and B4 and see if you can find what is hidden.

Row 4:
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`3     56    8    |169   4     169  |7     25    26`

And Box 4:
Code: Select all
`3     56    8    |1     467   9    |2     4567  46   |`

I just don't see anything that could lead me to eliminate numbers or to define numbers at specific cells. One more hint please.
JeJ

Posts: 76
Joined: 06 January 2011

### Re: Method for another Challenger sudoku

Ah, sorry. I meant B5, not B4.

Look for a hidden pair.

JasonLion
2017 Supporter

Posts: 640
Joined: 25 October 2007
Location: Silver Spring, MD, USA

### Re: Method for another Challenger sudoku

JasonLion wrote:Ah, sorry. I meant B5, not B4.

Look for a hidden pair.

A Hidden pair in B5? I don't see it. 1 is with 6 and 9, that is not a pair, 3 is with 6 and 7 again not a pair, 7 is with 3 and 6 same situation and 6 is with about everyone else. I am not as good at this as I thought or there is something missing from the theory I studied about pairs.
JeJ

Posts: 76
Joined: 06 January 2011

### Re: Method for another Challenger sudoku

1 and 9 is a hidden pair in both row 4 and block 5. There is also a naked triple in R4 that makes the same elimination: 2,5 and 6 in R4C289

JasonLion
2017 Supporter

Posts: 640
Joined: 25 October 2007
Location: Silver Spring, MD, USA

### Re: Method for another Challenger sudoku

I see it now. Thanks. This means I still have to work on my pair descovering abilities.
JeJ

Posts: 76
Joined: 06 January 2011