March 2, 2017

Post puzzles for others to solve here.

March 2, 2017

Postby ArkieTech » Thu Mar 02, 2017 12:45 am

Code: Select all
 *-----------*
 |...|1.9|.65|
 |7..|.4.|..8|
 |...|6..|.3.|
 |---+---+---|
 |.9.|...|..6|
 |6.7|4.5|8.3|
 |3..|...|.2.|
 |---+---+---|
 |.7.|..8|...|
 |8..|.3.|..2|
 |54.|9.6|...|
 *-----------*


Play/Print this puzzle online
dan
User avatar
ArkieTech
 
Posts: 2659
Joined: 29 May 2006
Location: NW Arkansas USA

Re: March 2, 2017

Postby SteveG48 » Thu Mar 02, 2017 1:34 am

Code: Select all
 *-----------------------------------------------------------------------------*
 | 24      3       248     | 1      e278     9       | 247     6       5       |
 | 7       156     1256    | 235     4       23      | 12      9       8       |
 | 1249    158     124589  | 6      d2578   d27      | 1247    3      c147     |
 *-------------------------+-------------------------+-------------------------|
 | 14      9       1458    | 2378   f27      1237    | 457     47      6       |
 | 6       2       7       | 4       9       5       | 8       1       3       |
 | 3       158     1458    | 78      6       17      | 4579    2       479     |
 *-------------------------+-------------------------+-------------------------|
 | 129     7       36      | 25     f125     8       | 36    ab4-5    b149     |
 | 8       16      169     | 57      3       4       | 169    b57      2       |
 | 5       4       123     | 9      f127     6       | 137     8      b17      |
 *-----------------------------------------------------------------------------*


4r7c8 = (1457)b9p2359 - (1|4=7)r3c9 - r3c56 = r1c5 - (7=125)r479c5 => -5 r7c8 ; stte

Fixed typo. Solution discussed below.
Last edited by SteveG48 on Thu Mar 02, 2017 3:34 pm, edited 1 time in total.
Steve
User avatar
SteveG48
2017 Supporter
 
Posts: 1994
Joined: 08 November 2013
Location: Orlando, Florida

Re: March 2, 2017

Postby Leren » Thu Mar 02, 2017 2:01 am

Code: Select all
*--------------------------------------------------------------------------------*
| 24      3       248      | 1       278     9        | 247     6       5        |
| 7       156     1256     | 235A    4       23A      | 12      9       8        |
| 1249    158     124589   | 6       2578    27A      | 1247    3      b147bB    |
|--------------------------+--------------------------+--------------------------|
| 14      9       1458     | 2378    27      1237     | 457     47      6        |
| 6       2       7        | 4       9       5        | 8       1       3        |
| 3       158     1458     | 78      6       17       | 4579    2       479      |
|--------------------------+--------------------------+--------------------------|
| 129a    7       36       | 25a     125a    8        | 36      45      149a     |
| 8       16      169      | 7-5     3       4        | 169    a57      2        |
| 5       4       123      | 9       127     6        | 137     8      a17       |
*--------------------------------------------------------------------------------*

3 Petal Death Blossom: Stem Cell r3c9 {147} :

(5=1) r8c8, r9c9  - (1) r3c9;

(5=4) r7c1459     - (4) r3c9;

(5=7) r2c46, r3c6 - (7) r3c9; => - 5 r8c4; stte

Leren
Leren
 
Posts: 2902
Joined: 03 June 2012

Re: March 2, 2017

Postby Alex_Popov_92 » Thu Mar 02, 2017 3:05 am

Code: Select all
 *-----------------------------------------------------------------------------*
 | 24      3       248     | 1       278     9       | 247     6       5       |
 | 7       156     1256    | 235     4       23      | 12      9       8       |
 | 1249    158     124589  | 6       2578    27      | 1247    3       147     |
 |-------------------------+-------------------------+-------------------------|
 | 14      9       1458    | 2378    27      1237    | 457     47      6       |
 | 6       2       7       | 4       9       5       | 8       1       3       |
 | 3       158     1458    | 78      6       17      | 4579    2       479     |
 |-------------------------+-------------------------+-------------------------|
 | 129     7       36      | 25      125     8       | 36      45      149     |
 | 8       16      169     | 57      3       4       | 169     5-7     2       |
 | 5       4       123     | 9       127     6       | 137     8       17      |
 *-----------------------------------------------------------------------------*

What to do but thank SteveG48 for his patience with me?!
Spent 10m for the logic and 3 hours to write this (simple for anybody but me!)
 code notation...
1. 1r3c9 - (1=7)r9c9 => r8c8<>7
2. 4r3c9 -  4r7c9 = (4-5)r7c8 =5r8c8 => r8c8<>7
3. 7r3c9 - 7r1c7  = 7r1c5 - 7r9c5 =7r8c4 => r8c8<>7
 => r8c8<>7; stte
I hope this time it is right...
Thank you Eleven for your patience.
But from your words I didn't get it if I should stay here or leave.
I am definitely for staying.
In the future I intend to mark my cells but today
I should have marked one and the same cell
with several letters. I preferred not to clutter the form. OK, I'll comply with this. Have a nice evening all of you guys.
Last edited by Alex_Popov_92 on Thu Mar 02, 2017 11:08 pm, edited 2 times in total.
Alex
Alex_Popov_92
 
Posts: 22
Joined: 22 February 2017

Re: March 2, 2017

Postby eleven » Thu Mar 02, 2017 7:29 am

SteveG48 wrote:4r7c8 = (1457)b9p2359

Hehe, using the strong link and last digit simultaneously is allowed now ?


Code: Select all
 *------------------------------------------------------------*
 | 24    3    248     |   1     278   9     |  247   6   5    |
 | 7     156  1256    |  a235   4    b23    | c12    9   8    |
 | 1249  158  124589  |   6     2578 b27    |  1247  3  c147  |
 |--------------------+---------------------+-----------------|
 | 14    9    1458    |   2378  27    1237  |  457   47  6    |
 | 6     2    7       |   4     9     5     |  8     1   3    |
 | 3     158  1458    |   78    6     17    |  4579  2   479  |
 |--------------------+---------------------+-----------------|
 |d129   7    36      | da25   d125   8     |  36    45 d149  |
 | 8     16   169     |   57    3     4     |  169   57  2    |
 | 5     4    123     |   9     127   6     |  137   8   17   |
 *------------------------------------------------------------*

(5=3)r27c4-(3=27)r23c6-(2|7=4)b3p49-(4=5)r7c1459 => -5r8c4, stte
eleven
 
Posts: 1564
Joined: 10 February 2008

Re: March 2, 2017

Postby bat999 » Thu Mar 02, 2017 12:47 pm

Code: Select all
.-------------------.----------------------.------------------.
| 24    3    248    |  1      278    9     |  247    6    5   |
| 7     156  1256   |  25-3   4     a23    | b12     9    8   |
| 1249  158  124589 |  6      2578  a27    |  1247   3   b147 |
:-------------------+----------------------+------------------:
| 14    9    1458   | e2378  e27     127-3 |  457   e47   6   |
| 6     2    7      |  4      9      5     |  8      1    3   |
| 3     158  1458   | e78     6      17    |  4579   2    479 |
:-------------------+----------------------+------------------:
| 129   7    36     |  25     125    8     |  36    d45  c149 |
| 8     16   169    | e57     3      4     |  169   e57   2   |
| 5     4    123    |  9      127    6     |  137    8    17  |
'-------------------'----------------------'------------------'
(3=27)r23c6 - (2|7=4)r2c7,r3c9 - r7c9 = r7c8 - (4=3)r4c458,r6c4,r8c48 => -3 r2c4,r4c6; stte
8-)
User avatar
bat999
2017 Supporter
 
Posts: 674
Joined: 15 September 2014
Location: UK

Re: March 2, 2017

Postby SteveG48 » Thu Mar 02, 2017 2:29 pm

eleven wrote:
SteveG48 wrote:4r7c8 = (1457)b9p2359

Hehe, using the strong link and last digit simultaneously is allowed now ?


I think I'd call it using a locked set and strong link simultaneously.

I suppose I could have written it 4r7c8 = (4r7c9)&(157b9p259). In fact, I think you're right. No, I know you're right. The next link, (1457)b9p2359 - (1|4=7)r3c9, is technically incorrect, since you don't know the position of the digits without "remembering" the first term. Not good. My solution should have been:

4r7c8 = (4r7c9)&(157b9p259) - (1|4=7)r3c9 - r3c56 = r1c5 - (7=125)r479c5 => -5 r7c8 ; stte
Last edited by SteveG48 on Thu Mar 02, 2017 3:33 pm, edited 1 time in total.
Steve
User avatar
SteveG48
2017 Supporter
 
Posts: 1994
Joined: 08 November 2013
Location: Orlando, Florida

Re: March 2, 2017

Postby Cenoman » Thu Mar 02, 2017 3:26 pm

Code: Select all
 +-----------------------+----------------------+-------------------+
 | 24     3     248      | 1     c278    9      |b247    6    5     |
 | 7      156   1256     | 235    4      23     | 12     9    8     |
 | 1249   158   124589   | 6      2578   27     | 1247   3   a147   |
 +-----------------------+----------------------+-------------------+
 | 14     9     1458     | 2378   27     1237   | 457    47   6     |
 | 6      2     7        | 4      9      5      | 8      1    3     |
 | 3      158   1458     | 78     6      17     | 4579   2   A479   |
 +-----------------------+----------------------+-------------------+
 | 129    7     36       | 25     125    8      | 36    B45  B149   |
 | 8      16    169      |C57z    3      4      | 169   B57y  2     |
 | 5      4     123      | 9      12-7   6      | 137    8    17x   |
 +-----------------------+----------------------+-------------------+

Kraken column (7)r369c9 => -7 r9c5; stte
Code: Select all
(7)r3c9 - r1c7 = (7)r1c5            -7r9c5
(7-9)r6c9 = (459-7)b9p235 = (7)r8c4 -7r9c5
(7)r9c9 - r8c8 = (7)r8c4            -7r9c5


A pity to use the kraken elephant gun for a puzzle solved with so simple AIC's as:
1. (7)r9c5 = r8c4 - (7=8)r6c4 - r4c4 = r4c3 - r1c3 = (8)r1c5 => -7 r1c5
2. Kite (7)r9c5 = r9c79 - r8c8 = r4c8 => -7 r4c5; stte

Cenoman
Last edited by Cenoman on Thu Mar 02, 2017 3:49 pm, edited 1 time in total.
Cenoman
 
Posts: 374
Joined: 21 November 2016
Location: Paris, France

Re: March 2, 2017

Postby SteveG48 » Thu Mar 02, 2017 3:27 pm

Alex_Popov_92 wrote:
Code: Select all
 *-----------------------------------------------------------------------------*
 | 24      3       248     | 1       278     9       | 247     6       5       |
 | 7       156     1256    | 235     4       23      | 12      9       8       |
 | 1249    158     124589  | 6       2578    27      | 1247    3       147     |
 |-------------------------+-------------------------+-------------------------|
 | 14      9       1458    | 2378    27      1237    | 457     47      6       |
 | 6       2       7       | 4       9       5       | 8       1       3       |
 | 3       158     1458    | 78      6       17      | 4579    2       479     |
 |-------------------------+-------------------------+-------------------------|
 | 129     7       36      | 25      125     8       | 36      45      149     |
 | 8       16      169     | 57      3       4       | 169     5-7     2       |
 | 5       4       123     | 9       127     6       | 137     8       17      |
 *-----------------------------------------------------------------------------*

1. 1r3c9 - (1=7)r9c9 => r8c8<>7
2. 4r3c9 - {4=19)r7c9 - (5=4)r7c8 - (7=5)r8c8 => r8c8<>7
3. 7r3c9 - (7=24)r1c7 - (28=7)r1c5 - (7=12)r9c5 - (5=7)r8c4 => r8c8<>7
 => r8c8<>7; stte


Alex, both chains 2 and 3 have problems. For example, in chain 2 you have (4=19)r7c9. This means both 1 and 9 are true in r7c9 (if 4 is false). That can't be true. Then you have (5=4)r7c8. Where is the link to the 5 from the preceding term? The next term has the same problem with the 7. All the issues are fixable, so please try again.
Steve
User avatar
SteveG48
2017 Supporter
 
Posts: 1994
Joined: 08 November 2013
Location: Orlando, Florida

Re: March 2, 2017

Postby Leren » Thu Mar 02, 2017 8:43 pm

Cenoman wrote :

A pity to use the kraken elephant gun for a puzzle solved with so simple AIC's as:
1. (7)r9c5 = r8c4 - (7=8)r6c4 - r4c4 = r4c3 - r1c3 = (8)r1c5 => -7 r1c5
2. Kite (7)r9c5 = r9c79 - r8c8 = r4c8 => -7 r4c5; stte

You won't be the first to express sentiments such as this and you won't be the last. I don't see why you can't combine these two moves into one :

Code: Select all
(7)r9c5 =  r8c4 - (7=8) r6c4 - r4c4 = r4c3 - r1c3 = (8) r1c5;

        \ r9c79 - r8c8                            = (7) r4c8; => - 7 r14c5; stte

That's not a kraken elephant gun, merely a split path Magnum 44 :D.

Leren
Leren
 
Posts: 2902
Joined: 03 June 2012

Re: March 2, 2017

Postby eleven » Thu Mar 02, 2017 9:23 pm

Alex_Popov_92 wrote:What to do but thank SteveG48 for his patience with me?!
Spent 10m for the logic and 3 hours to write this (simple for anybody but me!)
code notation...
1. 1r3c9 - (1=7)r9c9 => r8c8<>7
2. 4r3c9 - 4r7c9 = (4-5)r7c8 - (7=5)r8c8 => r8c8<>7
3. 7r3c9 - 7r1c7 = 7r1c5 - 7r9c5 =7r8c4 => r8c8<>7
=> r8c8<>7; stte
I hope this time is right!

Nice, that you stay ...

I just would suggest
2. 4r3c9 - 4r7c9 = (4-5)r7c8 = 5r8c8 => r8c8<>7

... and if you want to do us a favour, please mark the cells somehow in the grid.
eleven
 
Posts: 1564
Joined: 10 February 2008


Return to Puzzles