- Code: Select all
,-------------------,-------------------,--------------------,
| 69 69 b#1238 |b#123–7 57 1235 | 1348 12348 2348 |
| 4 *123 7 | 9 *123 8 | 5 b123 6 |
|*123 5 b123–8 | 6 4 *123 | 1378 12378 9 |
:-------------------+-------------------+--------------------:
|*123 8 6 | 5 *123 7 | 134 9 234 |
| 7 *123 9 | 4 68 *123 | 1368 5 238 |
| 5 4 a#123 |#1238 689 1239 | 13678 12378 2378 |
:-------------------+-------------------+--------------------:
| 369 369 345 | 378 5789 3459 | 2 3478 1 |
| 8 7 1234 |a123 b123 b1234 | 9 6 5 |
| 1239 1239 12345 | 12378 5789 6 | 3478 3478 3478 |
'-------------------'-------------------'--------------------'
There are 3 guardians, but they are all at the rectangle (#).
The 8-loop (*) has no guardians.
If b15* or b24* were restricted to the same two digits, it would break one of the other boxes.
Consequently, each of 123 can appear at the rectangle at most once.
The digit in r6c3, let's call it
a, must appear in b2* and is in c4 and r8 forced into b8. So
a must take r8c4.
The 1|2|3 in r13c3, let's call it
b, must appear in b5* and in r8
b is forced into c56. In c4
b must then take r1c4.
Therefore in b1
b takes r3c3 and in b3 r2c8. –7r1c4, –8r3c3
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,-------------------,------------------,--------------------,
| 69 69 8 |b123 7 5 | 134 1234 234 |
| 4 *123 7 | 9 *123 8 | 5 b123 6 |
|*123 5 b123 | 6 4 *123 | 78 78 9 |
:-------------------+------------------+--------------------:
|*123 8 6 | 5 *123 7 | 134 9 234 |
| 7 *123 9 | 4 68 *123 | 1368 5 238 |
| 5 4 a123 | 1238 689 1239 | 13678 78–123 2378 |
:-------------------+------------------+--------------------:
| 369 369 345 | 378 589 349 | 2 3478 1 |
| 8 7 1234 |a123 123 1234 | 9 6 5 |
| 1239 1239 12345 | 12378 589 6 | 3478 3478 3478 |
'-------------------'------------------'--------------------'
Another property of the 8-loop is that each digit can appear on it at most 3 times.
In b12, only
b appears outside the 8-loop.
The remaining two digits must do so in b45, which forces them into r6c346.
Together with
br2c8, each of 123 sees r6c8. –123r6c8
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,---------------,--------------,--------------,
| 69 69 8 |b12 7 5 | 34 12 34 |
| 4 *123 7 | 9 *123 8 | 5 b12 6 |
|*123 5 b23–1| 6 4 *123 | 7 8 9 |
:---------------+--------------+--------------:
|*123 8 6 | 5 *123 7 | 134 9 234 |
| 7 *123 9 | 4 6 *123 | 13 5 8 |
| 5 4 a3–12| 8 9 1–23| 6 7 23 |
:---------------+--------------+--------------:
| 36 36 5 | 7 8 9 | 2 4 1 |
| 8 7 12 |a3 12 4 | 9 6 5 |
| 129 129 4 | 12 5 6 | 8 3 7 |
'---------------'--------------'--------------'
In r8c4, we see that
a=3, so r6c3=3.
1r6 is forced into r6c6, outside the 8-loop. It must then appear on the 8-loop in b1. –1r3c3, stte
Marek