Is there a rule for this?

Advanced methods and approaches for solving Sudoku puzzles

Is there a rule for this?

Postby SuDokuKid » Fri Nov 04, 2005 10:17 pm

If these are the candidates:

26|267|67
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Postby simes » Fri Nov 04, 2005 10:40 pm

well, from that snippet, it's a bit hard to tell. It could be a naked triplet if those numbers don't appear in the other cells in the rol/col/block.

Care to post the entire puzzle? Or even the full row/column/block?

Simes
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Postby SuDokuKid » Fri Nov 04, 2005 10:50 pm

The column is:

26
9
4
267
67
3
8
1
5

I also have a row like this. I'm trying to 'see' triplets and pairs, etc. I'm having a hard time understanding right now.

{367}{3679}{5}|{4}{8}{2}|{1}{79}{67}
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Postby simes » Fri Nov 04, 2005 11:14 pm

Nope, not much there then.

If you had three cells with those candidates, and other unfilled cells in the same unit, you could eliminate 2, 6 and 7 from the candidates for those other cells.

but in this case, you haven't, so you can't.

S
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Postby SuDokuKid » Sat Nov 05, 2005 5:09 am

What about the row of candidates I displayed?
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Postby cho » Sat Nov 05, 2005 7:12 am

SuDokuKid wrote:The column is:

26
9
4
267
67
3
8
1
5

I also have a row like this. I'm trying to 'see' triplets and pairs, etc. I'm having a hard time understanding right now.

{367}{3679}{5}|{4}{8}{2}|{1}{79}{67}

You can't deduce anything from the data you provided except that the sevens are locked in the box they are in and can't be elsewhere in that box, and the same for the threes in your row. For example, if your row and column looked like this:
Code: Select all
*-----------+-----------+-----------*
|  .  .  .  |  .  .  .  |  .  .  26 |
|  .  .  .  |  .  .  .  |  .  .  9  |
|  .  .  .  |  .  .  .  |  .  .  4  |
+-----------+-----------+-----------+
|  .  .  .  |  .  .  .  |  .  .  267|
|367 3679 5 |  4  8  2  |  1  79 67 |
|  .  .  .  |  .  .  .  |  .  .  3  |
+-----------+-----------+-----------+
|  .  .  .  |  .  .  .  |  .  .  8  |
|  .  .  .  |  .  .  .  |  .  .  1  |
|  .  .  .  |  .  .  .  |  .  .  5  |
*-----------+-----------+-----------*

you could set r5c8 to nine since the seven has to be in r4c9 or r5c9.

cho
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Postby MCC » Sat Nov 05, 2005 12:49 pm

SuDokuKid wrote:What about the row of candidates I displayed?


Code: Select all
{367}{3679}{5}|{4}{8}{2}|{1}{79}{67}


The 3679 make up a naked quad.

As simes has implied you're not giving us much to go on.

If you want to post a grid with the position you've reached we may be able to help.
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Postby SuDokuKid » Mon Nov 07, 2005 9:05 pm

MCC wrote:
SuDokuKid wrote:What about the row of candidates I displayed?


Code: Select all
{367}{3679}{5}|{4}{8}{2}|{1}{79}{67}


The 3679 make up a naked quad.

As simes has implied you're not giving us much to go on.

If you want to post a grid with the position you've reached we may be able to help.


Here's what I have so far:

{8}{356}{236} | {7}{4}{9} | {256}{1}{26}
{1257}{157}{4} | {238}{6}{138} | {258}{357}{9}
{1267}{167}{9} | {238}{13}{5} | {268}{37}{4}

{4}{1679}{1267} | {69}{135}{137} | {2569}{8}{267}
{367}{3679}{5} | {4}{8}{2} | {1}{79}{67}
{1267}{8}{1267} | {69}{15}{17} | {24569}{4579}{3}

{567}{567}{67} | {1}{9}{4} | {3}{2}{8}
{9}{4}{38} | {5}{2}{38} | {7}{6}{1}
{13}{2}{138} | {38}{7}{6} | {49}{49}{5}
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Postby QBasicMac » Mon Nov 07, 2005 9:52 pm

SuDokuKid wrote:Here's what I have so far:


That's more like it! Easier to work from a complete puzzle.

From your current position, box 3 has 7 locked in column 8, so 7's can be eliminated from r56c8, right? This gives r5c8=9 and the rest solves easily.

Mac
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Postby SuDokuKid » Mon Nov 07, 2005 10:22 pm

Yes you're right. After that, I was able to solve it. I'm kicking myself for not seeing it.
Thank you.
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Postby cho » Tue Nov 08, 2005 6:54 am

QBasicMac wrote:
SuDokuKid wrote:Here's what I have so far:

From your current position, box 3 has 7 locked in column 8, so 7's can be eliminated from r56c8, right? This gives r5c8=9 and the rest solves easily.

Mac

That would be box 6 actuually as my lucky guess above indicates.:D

cho
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Postby QBasicMac » Tue Nov 08, 2005 1:54 pm

cho wrote:That would be box 6...


Not sure how you number boxes. Look at box Y below

xxx xxx YYY
xxx xxx YYY
xxx xxx YYY

xxx xxx xxx
xxx xxx xxx
xxx xxx xxx

xxx xxx xxx
xxx xxx xxx
xxx xxx xxx

I call that box 3. It's contents are
Code: Select all
{256}{  1}{26}
{258}{357}{ 9}
{268}{ 37}{ 4}


Do you see the 7's I am talking about?

I don't see how your "lucky guess" post is involved here.

Mac
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Postby cho » Wed Nov 09, 2005 4:16 am

QBasicMac wrote:
cho wrote:That would be box 6...


I don't see how your "lucky guess" post is involved here.

Mac

Because you could set R5c8 to 9 with just the info given before the whole puzzle was supplied with the sevens being locked in column nine in box six. Do you see that? But as I said, just a lucky guess.:)

But yes, I see you arrived at the same thing using box 3. I didn't notice the second set of locked candidates when reading your post.

cho
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