Is there such a thing as an invalid vertical swordfish? I was working on a puzzle and I thought I had established a swordfish of 7's, but the application of the swordfish method produced an invalid result.
The initial grid looks like this:
A2=2
A8=7
B4=5
B6=8
B9=4
D1=4
D5=3
D9=8
E2=7
E5=9
E8=2
F1=6
F5=1
F9=5
H1=5
H4=6
H6=4
H9=1
I2=3
I8=9
As you solve the puzzle, you will see that a vertical swordfish of 7's looks like it could be established at C4, D4, I4; C6, F6, I6; D7, F7. However, when you remove the 7's from C1, I1 and I9, you will notice two things: (1) removing the 7's from C1 and I1 makes G1 the only 7 remaining in Column 1. When you set G1 at 7, and remove the 7 from G9, column nine no longer has a cell for value 7.
If you have any insights into this issue, I would sure like to hear them.