First of all, your solution with AIC steps only is very nice !
I rewrite it my way, in two steps:
1. (7)r1c8 = (7-3)r1c6 = r1c9 - r5c9 = (3-7)r5c3 = (7)r5c8 Loop
=> -7 r6c8, + other loop eliminations (-1245 r1c6, -3 r34c9, -148 r5c3)
2. (7)r5c8 = (378)r5c319 - (7|8=1246)r6c1258 - (6=145)r5c456 => -145 r5c8; ste
-7r5c8 is the only elimination needed to validate your second step.
StrmCkr wrote:inference the aahs(124678) into a locked set
To me, r61258 is not an AAHS, but an AALS, the reason why I write it (7|8=1246)r6c1258 in the chain.
Before talking of notations, i'd like recall the definitions I use:
An ALS: n cells, subset of a sector, containing n+1 digits. Only one digit can be eliminated, leaving a naked subset.
An AALS contains n+2 digits (it is therefore an almost-almost naked subset)
An AHS: p cells, subset of a sector, containing n-1 locked digits within itself. Only one digit can be True, besides the locked digits, forming a hidden subset.
An AAHS contains n-2 locked digits.
I don't see 2 locked digits within r6c1258 (only the 2s are locked herein) On the contrary I see 6 digits in four cells forming diverse NQ with two spoilers => AALS.
So the third strong link has to be written (7|8=1246)r6c1258, with the OR symbol '|'
Otherwise (78=1246)r6c2358 would mean: whether NQ(1246)r6c2358 OR (78)r62358, term which means to me 7r6c2358 AND 8r6c2358. NQ(1246) is False if at least 1 out of the 4 digits is false, in which case 7 AND 8 can't be simultaneously True.
OK, all this is nitpicking
StrmCkr wrote:not exactly sure on how we use eureka to notate AHS ?
Concerning the AHS (378)r5c319, your writing and notations are Eureka compatible.
In the present puzzle, the AHS is used to provide weak links to candidates that are out of its sector. When used for internal weak links, I'd usually write e.g. (738-6)r5c139, were such a link useful. With the following rules: linking digits at the right and left side, bystanders (locked digits) appended to the left side linking digit. The bystanders could be written at the right side as well without any change to the logic.
If you would focus on the 7,8 being @r6c13, you could use the notation (3,7,8)r6c931 where the commas mean that the digits are ordered the same as the cells behind.
Here, such a notation is not required, since the digits have only one arrangement possible in the cells.
StrmCkr wrote:what else can we do on this grid?
As already shown by other players, the grid can be solved in one step:
- Code: Select all
+------------------------+---------------------------+--------------------------+
| 128 12458 12458 | 1245 9 123457 | 6 1245-7 1234 |
| 3 1245 69 | 12456 14567 124567 | z14579 8 1249 |
| 7 1245 69 | 12456 8 123456 | 13459 12459 12349 |
+------------------------+---------------------------+--------------------------+
| 126 1234 1234 | 7 12456 8 | 13459 1459 13469 |
| 168 9 a13478 | B1456 B1456 B1456 | 2 Ba1457 a13468 |
| 5 12478 12478 | 3 A1246 9 | z1478 147 A1468 |
+------------------------+---------------------------+--------------------------+
| 129 127 127 | 8 1467 12467 | 149 3 5 |
| 4 12358 12358 | 1259 135 125 | y189 6 7 |
| 189 6 13578 | 1459 13457 1457 | y1489 1249 x12489 |
+------------------------+---------------------------+--------------------------+
Kraken column (8)r569c9
(837)r5c389
(86)r6c59 - (6=1457)r5c4568
(8)r9c9 - r89c7 = (87)r26c7
=> -7 r1c8; ste