Idea of Twins

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Idea of Twins

Postby Elzo Nguyen » Sun Sep 11, 2011 1:28 am

Some thing I write here maybe someone already know. However, I need help for this idea that I named Twins.
Terms:
1. Strong cells:
When there are two candidates in a house, they make a strong link. Their cells are called strong cells.
2. Hidden strong link:
When there are more than two candidates in a box, two of them would make a strong link if the others are eliminated. They are called hidden strong link. Their cells are called hidden strong cells.

Twins:
Twins are a combination of two cycles of strong cells and hidden strong cells in four boxes or more.

Structure:
There is only one strong link or hidden strong link in a house (box, row, column) throughout the Twins.
Each cell of the cycle 1 is a peer of three other cells of the cycle 2 in box, row and column, except when they are in the same line in box.
Candidates that are not in any cycles of Twins are Not-Twins Cells and can be eliminated.
X-Wing and Uniqueness are parts of Twins.

True and False Twins:
True Twins can be almost completed by starting from many or any of their cells of one cycle and the structure does not change.
False Twins can be completed by starting at only one cell of their cycle and the result is that this starting cell does not contain candidate. Starting from other cell of the cycle, you can not complete the Twins.

Types of Twins:
Complete Twins: when two cycles of Twins can be made paired in boxes that contain candidates. All candidates of Not-Twin cells can be eliminated.
X-Twins: when a cycle leaves four cells undetermined and at least one of these four cells can belong to any cycle. Cycle that causes a X-Twins contains solved digit.
U-Twins: or (Uniqueness-Twins) when a cycle leaves four cells undetermined and all of them belong to one cycle. The cycle that an U-Twins is involved does not contain the solved digit. So, the other cycle has solved digit.
(correction: The cycle that causes U-Twins does not contain solved digit. U-Twins contain solved digit, and so its cycle contains solved digit too).( Very sorry for mistakes)
Locked Twins: when the same Twins can be started from two cells in a box. These two cells work like a pointing pair and all candidates on the same line outside the box can be eliminated.

How to find out a Hidden Strong Cell:
1. In a house, there are not two cells of the same cycle.
2. One cell of a strong link belongs to cycle 1 and the other cycle 2.
3. On a line (row, column) of three candidates, one cell belongs to the cycle 1, another belongs to the cycle 2 if this cell is the only cell outside the box that contain two others; or this cell has a strong link with another cell in its box when each candidate of the three belongs to one box different.
On a line of four or more candidates, a hidden strong cell can not be determined even when they have a strong link, because there are always two cells can have hidden strong link. This is when X-Twins or U-Twins happen.
4. In a house, a cell can be a hidden strong cell when no other cells can do.
5. When two cells of the same cycle are found in the same house, this cycle become invalid and the starting cell of the cycle does not contain the candidate.

This example from Sudocue-top10000 collection number 10
Copy Values after some moves:
76.9....3.2.3.7..6.3462.7..1..752.34.4319657..7.834..9..74813..4..5.3.8.3..2.9.4.

(Please see attachment for image 1)
false Twins 8 from cell r4c2
Cycle 1 blue Cycle 2 red
Twins cover boxes 1,2,3,4,6 and7.
The only cell to start these Twins is r4c2; Twins can not be completed if the starting cell is r5r9, r3c6 r2c1 ... of the cycle 1.

From the same example , Twins 8, starting from r1c7, cover boxes 1, 2, 3, 4 and 6 and leave X-Wing in boxes 4 ,7.

(Please see attachment for image 2)
true Twins 8 from r1c7 or X-Twins 8

These Twins can be started from any blue cell: r1c7, r2c1, r3c6 or r5c9.
Cycle 1 (blue) leaves four cells undetermined r4c23 and r9c23, these cells belong to cycle 1, except r9c2 belongs to both cycle. And so, they make a X-Twins. The result is that all blue cells contain solved digit 8.
Thank you for your help, any correction will be much appriciated.
Elzo Nguyen.
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Re: Idea of Twins

Postby Elzo Nguyen » Sun Sep 11, 2011 8:41 pm

I apology for some mistakes. Here is my correction sent in pdf attachment.
Please accept my demand for pardon.
Thank you.
Elzo nguyen.
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Re: Idea of Twins

Postby ronk » Mon Sep 12, 2011 11:17 am

Elzo Nguyen wrote:These Twins can be started from any blue cell: r1c7, r2c1, r3c6 or r5c9.
Cycle 1 (blue) leaves four cells undetermined r4c23 and r9c23, these cells belong to cycle 1, except r9c2 belongs to both cycle. And so, they make a X-Twins. The result is that all blue cells contain solved digit 8.

Sorry Elzo, but using templates for digit <8> of your pencilmarks shows that the only valid elimination is r1c3<>8.

Code: Select all
 .  . -8 |  .  .  8 |  8  .  .
 8  .  8 |  .  .  . |  8  .  .
 8  .  . |  .  .  8 |  .  .  8
---------+----------+----------
 .  8  8 |  .  .  . |  8  .  .
 8  .  . |  .  .  . |  .  .  8
 .  .  . |  8  .  . |  .  .  .
---------+----------+----------
 .  .  . |  .  8  . |  .  .  .
 .  .  . |  .  .  . |  .  8  .
 .  8  8 |  .  .  . |  .  .  .

I haven't figured out what you're doing, so I can't pinpoint your error.
ronk
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Re: Idea of Twins

Postby Elzo Nguyen » Mon Sep 12, 2011 12:10 pm

Thank you ronk for your reply.
Solving sudoku, we encounter some patterns like ER with three boxes and a lot of other things.
I figure out a so-called "hidden strong link" in a box, and try to solve it.
Instead of an elimination of some candidates, Twins some times can find out some digits, and so, the game will be solved faster.
I don't know if it was unreliable?
(correction: should read "if it was reliable or not?)
Many thanks for help.
N.B.: If there is some thing impolite in my text, the main reason is my poor english.
Elzo Nguyen
 
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Re: Idea of Twins

Postby eleven » Mon Sep 12, 2011 4:34 pm

Hi Elzo,

i dont know, how you construct your cycles, but you seem to believe, that e.g.
if r4c2 is not 8, then r4c7 must be 8 (because it cant be blue then)

But this is not true.
eleven
 
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Re: Idea of Twins

Postby Elzo Nguyen » Mon Sep 12, 2011 9:33 pm

Hi eleven,
r4c2, r4c3, r9c3 and r9c2 are parts of what I call X-Twins .
In row 49 and column 23, I can not determine which cell is a "hidden strong cell".
In column 3, there are two cells (r4c3 & r9c3) that can act as hidden strong cell for r2c3. The best choice is for r4c3, because it is in the intersection of three cells r2c3 (column),r4c7 (row) and r5c1 (box), however, nothing is sure for that, because the presence of r9c3 in this line. The only thing sure is that these four cells belong to blue cycle, only r9c2 can be in red cycle. Cell r4c7 is just a " hidden strong cell" for either r4c2 or r4c3, but we dont know exactly by now. Cells r4c7 and r5c9 are strong link, r5c9 is blue so r4c7 must be red in this example. As strong link, if blue cycle is true then red cycle is wrong , and vice versa. So they are "strong cycle". In this example, blue cycle is true, so r4c7 <8>
I mention in my text some principles to find out a hidden strong cell. To construct Twins. it is easy to fall in trap, because , as I had written, there are false and true Twins.
Thank you for your reply.
Elzo Nguyen
 
Posts: 8
Joined: 11 September 2011

Re: Idea of Twins

Postby eleven » Tue Sep 13, 2011 8:09 am

Again, for the case you are not just fooling us:

You are claiming, that for this distribution of the 8's the blue (B) cells must be true?
Code: Select all
 .  .  8 |  .  . R8 | B8  .  .
B8  . R8 |  .  .  . |  8  .  .
 8  .  . |  .  . B8 |  .  . R8
---------+----------+----------
 . B8  8 |  .  .  . | R8  .  .
R8  .  . |  .  .  . |  .  . B8
 .  .  . |  8  .  . |  .  .  .
---------+----------+----------
 .  .  . |  .  8  . |  .  .  .
 .  .  . |  .  .  . |  .  8  .
 . R8  8 |  .  .  . |  .  .  .


If so, you made a complex construct based on a wrong assumption, because obviously this is a valid distribution for the 8's.
Code: Select all
 .  .  . |  .  .  8 |  .  .  .
 .  .  . |  .  .  . |  8  .  .
 8  .  . |  .  .  . |  .  .  .
---------+----------+----------
 .  .  8 |  .  .  . |  .  .  .
 .  .  . |  .  .  . |  .  . *8
 .  .  . |  8  .  . |  .  .  .
---------+----------+----------
 .  .  . |  .  8  . |  .  .  .
 .  .  . |  .  .  . |  .  8  .
 . *8  . |  .  .  . |  .  .  .
eleven
 
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Re: Idea of Twins

Postby Elzo Nguyen » Tue Sep 13, 2011 8:53 am

Thank you eleven for reply.
I ask for help to explain my idea.
Now I know it is a lucky move.
So I stop my works here.
Elzo Nguyen
 
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Joined: 11 September 2011


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