1St
r2c2=2 r3c3=8 r3c8=2
I though that since both ends of the chain "see" both r2c7 and r2c8 that the (2's) could be eliminated. No so.
2nd
r6c3=2 r6c9=8 r4c2
Here I thought that (2) could be excluded from r4c2. Again. not so.
3rd
r4c7=1 r7c7=2 r7c8=1
Here you can eliminate (1) from r5c8
Now why in two of the three cases are different. Please , I hope someone can explain this to me. Is my assumption that a candidate can be excluded if it "sees" both ends of a chain. Yep, I need help.
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*-----------*
|139|258|476|
|7.6|143|..9|
|54.|976|3.1|
|---+---+---|
|6.3|.97|.4.|
|9..|462|7.3|
|47.|.31|69.|
|---+---+---|
|397|685|..4|
|264|719|835|
|851|324|967|
*-----------*
*--------------------------------------------------*
| 1 3 9 | 2 5 8 | 4 7 6 |
| 7 28 6 | 1 4 3 | 25 258 9 |
| 5 4 28 | 9 7 6 | 3 28 1 |
|----------------+----------------+----------------|
| 6 12 3 | 58 9 7 | 15 4 28 |
| 9 18 58 | 4 6 2 | 7 15 3 |
| 4 7 25 | 58 3 1 | 6 9 28 |
|----------------+----------------+----------------|
| 3 9 7 | 6 8 5 | 12 12 4 |
| 2 6 4 | 7 1 9 | 8 3 5 |
| 8 5 1 | 3 2 4 | 9 6 7 |
*--------------------------------------------------*