Help with Fiendish puzzle, Times 3/1/07 No. 1122

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Help with Fiendish puzzle, Times 3/1/07 No. 1122

Postby silvercar » Wed Jan 03, 2007 7:29 pm

Anyone managed to do this?

Even used sudokusolver that said it can't be solved without an error!:(
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re: The Times #1122 (2007.Jan.3) - Fiendish

Postby Pat » Fri Jan 05, 2007 10:16 am

silvercar wrote:
    Fiendish puzzle, Times 3/1/07 No. 1122

    Anyone managed to do this?

    Even used sudokusolver that said it can't be solved without an error!


you should be able to solve it with "hidden singles" + "hidden" subsets.

The Times (2007.Jan.3) wrote:
        #1122

        [ 28 clues ]

        Fiendish
Code: Select all
 . 9 . | 8 6 . | 2 . .
 . . . | 4 . . | . . 7
 6 . 2 | . . 7 | 8 . .
-------+-------+------
 . . 6 | . . . | . 3 2
 4 . . | . . . | . . 1
 8 3 . | . . . | 6 . .
-------+-------+------
 . . 1 | 5 . . | 9 . 6
 5 . . | . . 2 | . . .
 . . 3 | . 1 4 | . 2 .


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Postby daj95376 » Fri Jan 05, 2007 5:35 pm

Pat,

The puzzle you posted can be solved with Naked Pairs. No need for hidden subsets.
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Postby udosuk » Fri Jan 05, 2007 5:47 pm

daj95376 wrote:The puzzle you posted can be solved with Naked Pairs. No need for hidden subsets.

If you're doing a puzzle on paper using a pen without making any pencilmark I suppose hidden subsets are easier to spot than naked pairs...
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re(2): The Times #1122 (2007.Jan.3) - Fiendish

Postby Pat » Sun Jan 07, 2007 10:38 am

daj95376 wrote:
    The puzzle can be solved with Naked Pairs.
    No need for hidden subsets.
    i said subsets as a general term,
    so as not to specify the size (duo, trio, quartet)
    -- no need to give away the solution-path.
      my preference is for "hidden" subsets,
      but i do admit there is a tradeoff --
      e.g., a "hidden" quartet would be tougher than a "naked" duo

    my original response was merely intended to tell silvercar
    that the puzzle is OK -- that there's no error -- and also not too tough;

    therefore, i quickly used software-screening of the puzzle,
    and announced the results
    (without spoiling the puzzle for myself).

      but "hidden singles" + "hidden" subsets
      is not necessarily the simplest solution-path;

      later, when i did solve the puzzle myself,
      i found myself using
        a "hidden" duo
        + a line-to-box exclusion,
      and also needing a couple of "naked singles".
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