The New Sudoku Players' Forum

[silvercar]

Anyone managed to do this?

Even used sudokusolver that said it can't be solved without an error!

[Pat]

Fiendish puzzle, Times 3/1/07 No. 1122

Anyone managed to do this?

Even used sudokusolver that said it can't be solved without an error!

you should be able to solve it with "hidden singles" + "hidden" subsets.

#1122

[ 28 clues ]

Fiendish

Code: Select all

 . 9 . | 8 6 . | 2 . .
 . . . | 4 . . | . . 7
 6 . 2 | . . 7 | 8 . .
-------+-------+------
 . . 6 | . . . | . 3 2
 4 . . | . . . | . . 1
 8 3 . | . . . | 6 . .
-------+-------+------
 . . 1 | 5 . . | 9 . 6
 5 . . | . . 2 | . . .
 . . 3 | . 1 4 | . 2 .



[daj95376]

Pat,

The puzzle you posted can be solved with Naked Pairs. No need for hidden subsets.

[udosuk]

The puzzle you posted can be solved with Naked Pairs. No need for hidden subsets.

If you're doing a puzzle on paper using a pen without making any pencilmark I suppose hidden subsets are easier to spot than naked pairs...

[Pat]

The puzzle can be solved with Naked Pairs.
No need for hidden subsets.

i said subsets as a general term,
so as not to specify the size (duo, trio, quartet)
-- no need to give away the solution-path.

my preference is for "hidden" subsets,
but i do admit there is a tradeoff --
e.g., a "hidden" quartet would be tougher than a "naked" duo

my original response was merely intended to tell silvercar
that the puzzle is OK -- that there's no error -- and also not too tough;

therefore, i quickly used software-screening of the puzzle,
and announced the results
(without spoiling the puzzle for myself).

but "hidden singles" + "hidden" subsets
is not necessarily the simplest solution-path;

later, when i did solve the puzzle myself,
i found myself using
a "hidden" duo
+ a line-to-box exclusion,
and also needing a couple of "naked singles".