Help with a 'hard' puzzle...

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Help with a 'hard' puzzle...

Postby cwgannon » Mon Jan 30, 2006 4:36 am

As you can imagine, I'm new at this. This 'hard' puzzle has me stuck a bit, and I can't seem to see why.

It began as:
Code: Select all
. . . | . 8 2 | . 9 .
. . . | 4 . . | . . .
. 2 5 | . . 3 | 7 1 .
------+-------+------
4 . 3 | . 5 . | . . .
. . 7 | . . . | 9 . .
. . . | . 4 . | 3 . 6
------+-------+------
. 7 8 | 6 . . | 1 2 .
. . . | . . 7 | . . .
. 9 . | 8 3 . | . . .


And I now have it here:
Code: Select all
7   14   14  |  5    8   2    |  6  9  3
69  3    69  |  4    7   1    |  5  8  2
8   2    5   |  9    6   3    |  7  1  4
-------------+----------------+----------
4   18   3   |  71   5   986  |  2  7  18
56  56   7   |  3    12  86   |  9  4  18
29  18   29  |  271  4   98   |  3  5  6
-------------+----------------+----------
3   7    8   |  6    9   4    |  1  2  5
56  456  46  |  21   21  7    |  8  3  9
12  9    12  |  8    3   5    |  4  6  7


I know it's nothing complicated, but it's the first time I've encountered such a situation, and I'm looking to understand how to go further, rather than just guessing my way through the rest of it.

Thanks.
cwgannon
 
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Joined: 29 January 2006

Postby tso » Mon Jan 30, 2006 6:27 am

You've made a mistake. Your current candidate grid is in error. The simplest thing to do -- maybe the only thing to do -- is start over.
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Postby cwgannon » Mon Jan 30, 2006 7:26 am

That's unfortunate. I'll update this post again, then, when I've done so if I get stuck again.

Thanks.
cwgannon
 
Posts: 6
Joined: 29 January 2006

Re: Help with a 'hard' puzzle...

Postby ronk » Mon Jan 30, 2006 1:17 pm

cwgannon wrote:I'm looking to understand how to go further, rather than just guessing my way through the rest of it.

tso wrote:You've made a mistake. Your current candidate grid is in error. The simplest thing to do -- maybe the only thing to do -- is start over.

But the digits placed are correct, so you really only need to redo the candidates.
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Re: Help with a 'hard' puzzle...

Postby QBasicMac » Mon Jan 30, 2006 3:25 pm

ronk wrote:so you really only need to redo the candidates.


True. Most notable: there is a 7 placed at r4c8, but a pencilmark unerased at r4c4.

Mac
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Postby cwgannon » Mon Jan 30, 2006 5:23 pm

Well, that solved it.

Thanks for all the help.
cwgannon
 
Posts: 6
Joined: 29 January 2006

Postby Locqueneux » Thu Feb 02, 2006 4:41 pm

Dans le carré central,le 7 est obligatoirement en bas ,à gauche(colonne 4;rangée 6).En effet,il ne peut y avoir de 7 dans les colonnes 5 et 6 ni dans les rangées 4 et 5 .
Il y avait une autre solution un peu moins évidente :
Dans le carré milieu/gauche le 9 ne peut être qu'en r6;c1 ou r6;c3 ce qui est d'ailleurs confirmé par vos candidats .
De ce fait, dans le carré central,le 9 ne peut être que dans la rangée4 et dans la colonne 6!
Bonne continuation.
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Postby Animator » Thu Feb 02, 2006 7:15 pm

Locqueneux: The question is asked in English, the answers so far are given in English and yet you decide to respond in French? If you want that most people can understand your message then you should write it in English. (If you do so then you might get some 'feedback' on it aswell...)
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