The Jackle wrote:"Can you tell me if this is wrong or right? And if wrong where did i go wrong?.."

Sorry Jackle but your answer is wrong. Although it is mentioned in the above link, I should have emphasized that the numbers 1 to 9 can only

appear

once in any row, column or box.

Your "solution" is incorrect because it shows:

two 5's in row 2

two 6's in row 3

two 6's in row 8

two 5's in row 9

two 3's in column 4

two 6's in column 6

Whilst you have the correct numbers in Box4 I suggest you start from scratch again.

When placing a number and again suggesting you start with Box 5, make sure the number you place does not already exist in the same row or

column. To better illustrate this, you incorrectly placed the

6 in cell r5c6 but overlooked that a

6 already existed in the same column 6. The correct placement for the

6 was in cell r5c4 because there was no 6 in column 4 or row 5. A

7 would then fill the remaining cell r5c6 in Box 5 and you should do a final check that there are no other 7's either in column 6 or row 5.

I emphasize the need to make haste slowly and particularly to check

both the corresponding row and column relating to the particular cell you place a number in. Good luck but it looks like some more homework Jackle

PS. I've noticed HATMAN has replied but decided to let my post stay to help (I hope) Jackle know where he went wrong.

Cec