by SteveF » Thu Aug 04, 2005 7:04 am
Unfortunately the problems last weekend led to the elimination of my previous post and I havn't been able to login since then. Here goes again.
Following on from emalvick's post, after step 3 (ie before looking for a turbot fish) it is possible to eliminate some 6's from box 1 because of where 6's must go in column 3.
It is then possible to eliminate 6 from r3c5 based on colours, using the chain r6c5, r6c9, r4c7, r3c7).
You now have a naked pair in row 3 allowing further eliminations, some eliminations from box 8 because of where candidates must go in column 4, and ditto for box 9.
There is now a swordfish which allows the elimination of 6 from r1c4 (rows 1,2,6, columns 3,5,9).
This allows eliminations from column 4.
Now use colouring on the 3's, eg starting with the r1c2, r2c1 pair and colouring all the possible pairs. It becomes obvious that the colour assigned to r2c1 must be the false colour as it gives two cells in column 5 with the same colour (and other inconsistencies).
Thus you can eliminate 3 from r1c4, r2c1, r2c6, r4c8, r5c2, r6c5 and r7c5.
Things get easier from then on.
I now need to look into this turbot fish possibility as it looks to be a lot quicker than the above.