Help again!!

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Help again!!

Postby asdfgh » Wed Feb 10, 2016 2:55 pm

Here we go for one more:

12937.84.
7489.1.2.
5638249..
83..9.2.4
45...2.9.
69274.1..
2854.9...
3.62..4.9
9.4.....2

Help me please! ^^
Thank you.
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Re: Help again!!

Postby StrmCkr » Wed Feb 10, 2016 5:30 pm

Code: Select all
.-----------.-----------------.------------------.
| 1  2   9  | 3    7      56  | 8    4      56   |
| 7  4   8  | 9    56     1   | 356  2      356  |
| 5  6   3  | 8    2      4   | 9    17     17   |
:-----------+-----------------+------------------:
| 8  3   17 | 156  9      56  | 2    67     4    |
| 4  5   17 | 16   38     2   | 367  9      3678 |
| 6  9   2  | 7    4      38  | 1    35     358  |
:-----------+-----------------+------------------:
| 2  8   5  | 4    136    9   | 367  1367   1367 |
| 3  17  6  | 2    158    78  | 4    158    9    |
| 9  17  4  | 56   13568  378 | 356  13568  2    |
'-----------'-----------------'------------------'


basics bring you to this point
2-String Kite: 5 in r2c7,r8c5 (connected by r8c8,r9c7) => r2c5<>5
then singles to the end
Last edited by StrmCkr on Thu Feb 11, 2016 7:37 pm, edited 1 time in total.
Some do, some teach, the rest look it up.
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Re: Help again!!

Postby asdfgh » Wed Feb 10, 2016 7:12 pm

Thank you for replying StrmCkr .

But I have a question.

To be a 2 String-Kite, it can only have 2 candidates in each row or colum, isn't it?

Why can I assume that there is a 2 String-Kite in row 8, since I have 3 cell that can be 5?

Thank you
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Re: Help again!!

Postby Leren » Thu Feb 11, 2016 9:45 am

Code: Select all
*--------------------------------------------------------------*
| 1     2     9      | 3     7     56     | 8     4     56     |
| 7     4     8      | 9     6-5   1      |d356   2     356    |
| 5     6     3      | 8     2     4      | 9     17    17     |
|--------------------+--------------------+--------------------|
| 8     3     17     | 156   9     56     | 2     67    4      |
| 4     5     17     | 16    38    2      | 367   9     3678   |
| 6     9     2      | 7     4     38     | 1     35    358    |
|--------------------+--------------------+--------------------|
| 2     8     5      | 4     136   9      | 367   1367  1367   |
| 3     17    6      | 2    a158   78     | 4    b158   9      |
| 9     17    4      | 56    13568 378    |c356   13568 2      |
*--------------------------------------------------------------*

I think StrmCkr had the wrong PM. Basics bring you to here, where there is a Kite in cells marked abcd, that removes 5 from r2c5 and solves the puzzle.

Note the naked pair 56 in r14c6 that removes the 5 from r8c6.

Also, a Kite can have more than 2 candidates in its row and column, as long as there is only 1 candidate in the row and column outside of the Kite box. In fact, the Kite box could, in theory, have up to 8 instances of the Kite candidate. The only position in the Kite box that can't have the Kite candidate is at the intersection of the row and column (r8c7 here).

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Re: Help again!!

Postby StrmCkr » Thu Feb 11, 2016 7:38 pm

yah I had the wrong pm grid, i corrected the grid above.
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