## Help again!!

Post the puzzle or solving technique that's causing you trouble and someone will help

### Help again!!

Here we go for one more:

12937.84.
7489.1.2.
5638249..
83..9.2.4
45...2.9.
69274.1..
2854.9...
3.62..4.9
9.4.....2

Thank you.
asdfgh

Posts: 6
Joined: 21 January 2016

### Re: Help again!!

Code: Select all
`.-----------.-----------------.------------------.| 1  2   9  | 3    7      56  | 8    4      56   || 7  4   8  | 9    56     1   | 356  2      356  || 5  6   3  | 8    2      4   | 9    17     17   |:-----------+-----------------+------------------:| 8  3   17 | 156  9      56  | 2    67     4    || 4  5   17 | 16   38     2   | 367  9      3678 || 6  9   2  | 7    4      38  | 1    35     358  |:-----------+-----------------+------------------:| 2  8   5  | 4    136    9   | 367  1367   1367 || 3  17  6  | 2    158    78  | 4    158    9    || 9  17  4  | 56   13568  378 | 356  13568  2    |'-----------'-----------------'------------------'`

basics bring you to this point
2-String Kite: 5 in r2c7,r8c5 (connected by r8c8,r9c7) => r2c5<>5
then singles to the end
Last edited by StrmCkr on Thu Feb 11, 2016 7:37 pm, edited 1 time in total.
Some do, some teach, the rest look it up.

StrmCkr

Posts: 889
Joined: 05 September 2006

### Re: Help again!!

Thank you for replying StrmCkr .

But I have a question.

To be a 2 String-Kite, it can only have 2 candidates in each row or colum, isn't it?

Why can I assume that there is a 2 String-Kite in row 8, since I have 3 cell that can be 5?

Thank you
asdfgh

Posts: 6
Joined: 21 January 2016

### Re: Help again!!

Code: Select all
`*--------------------------------------------------------------*| 1     2     9      | 3     7     56     | 8     4     56     || 7     4     8      | 9     6-5   1      |d356   2     356    || 5     6     3      | 8     2     4      | 9     17    17     ||--------------------+--------------------+--------------------|| 8     3     17     | 156   9     56     | 2     67    4      || 4     5     17     | 16    38    2      | 367   9     3678   || 6     9     2      | 7     4     38     | 1     35    358    ||--------------------+--------------------+--------------------|| 2     8     5      | 4     136   9      | 367   1367  1367   || 3     17    6      | 2    a158   78     | 4    b158   9      || 9     17    4      | 56    13568 378    |c356   13568 2      |*--------------------------------------------------------------*`

I think StrmCkr had the wrong PM. Basics bring you to here, where there is a Kite in cells marked abcd, that removes 5 from r2c5 and solves the puzzle.

Note the naked pair 56 in r14c6 that removes the 5 from r8c6.

Also, a Kite can have more than 2 candidates in its row and column, as long as there is only 1 candidate in the row and column outside of the Kite box. In fact, the Kite box could, in theory, have up to 8 instances of the Kite candidate. The only position in the Kite box that can't have the Kite candidate is at the intersection of the row and column (r8c7 here).

Leren
Leren

Posts: 3319
Joined: 03 June 2012

### Re: Help again!!

yah I had the wrong pm grid, i corrected the grid above.
Some do, some teach, the rest look it up.

StrmCkr

Posts: 889
Joined: 05 September 2006