Some while back Tso posed the following in response to someone asking for harder puzzles:
xxx|1xx!7xx
x2x|69x|xxx
9xx|xx3|x82
========
xxx|xxx|46x
64x|xxx|x57
x58|xxx|xxx
========
21x|8xx|xx9
xxx|x16|x7x
xx4|xx2|xxx
Firstly, has a solution (short of tabling) been posted for this one?
Secondly, while chasing round the bilocation/bivalue plot I noticed that there were occasions when one can go from a multi-candidate bilocation cell to a bivalue cell with quite useful looking short term results. Obviously this is directional and in no case actually led to any resolution about a cell but it left me wondering if there are generalisable circumstances where this might be useful, say for non-cyclic conflicting cell cases.