The New Sudoku Players' Forum

by **Paulie** » Mon Aug 08, 2005 3:24 pm

Newbie stuck on this one. Maybe I need to sleep on it.

*52*8173*
*38**7***
7412368**
183*2***7
2***7***8
57**982*3
425869371
3**71*58*
817****6*

Thx. for any help.

[/img]

by **SteveF** » Mon Aug 08, 2005 3:32 pm

Have a good look at column 8. There is a cell which is the only place one candidate can go.

by **Addlan** » Mon Aug 08, 2005 3:37 pm

Look at r2c8, '2' is the only possible digits in the column, so r2c8 = '2'. r2c7 = '1' because it is the only digit in the row. Look at r1c9 and r2c9, '4' and '6' are the only digits in that block, so (r1c9, r2c9) = (4, 6) -- naked pair. So r3c9 = 5 ......

by **Paulie** » Mon Aug 08, 2005 3:48 pm

Thx. guys for unblocking my mental block.

by **Paulie** » Mon Aug 08, 2005 4:07 pm

Hi. Sorry. But I am not sure how we can say for sure that r3c9 is 5 and not 9.
Thx.

Just trying to learn.

by **Addlan** » Mon Aug 08, 2005 4:12 pm

Paulie wrote:Hi. Sorry. But I am not sure how we can say for sure that r3c9 is 5 and not 9.
Thx.

Just trying to learn.

After the naked pair, you have eliminated other digits in those two grids except '4' and '6'. Then '5' must be there because in column 9 there is only one '5' there.

by **Paulie** » Mon Aug 08, 2005 4:16 pm

Thx. a lot. It seems so simple now!

by **Addlan** » Mon Aug 08, 2005 4:29 pm

Paulie wrote:Thx. a lot. It seems so simple now!

I am glad you have found the answer.

The New Sudoku Players' Forum

Hard Medium

Hard Medium

I've seen the light

r3c9

Re: r3c9