Jeff wrote:Double implication means 2 implication streams. Derived from this, Single implication means one implication stream.
I maintain that one implication stream does not a contradiction make.
Carcul wrote:Now, we can write the following (complicated) Single Implication Network:
[r1c8](-1-[r1c156])-1-[r146c9]-2,4,9-[r9c9](-6-[r9c34])-6-[r9c1](-8-[r9c5]=8=[r8c6]-8-[r1c6])-8-[r1c1]-7-[r1c6]-5-[r4c6](-4-[r4c9]-9-[r1c9]-2-[r1c2])=5=[r4c4]-5-[r9c4]-9-[r9c3]-2-[r7c2]
Holy (
use your favorite Robin expression here), Batman! For that same puzzle, let's work with something simpler.
Carcul wrote:- Code: Select all
178 2789 3 | 4 158 1578| 6 12789 129
14678 5 1267| 167 1368 9 | 2348 12478 1234
14678 4789 1679| 2 1368 1678| 3489 14789 5
----------------+----------------+-----------------
2 6 8 | 59 7 45 | 1 3 49
134 34 15 | 8 149 12 | 2459 6 7
9 47 157 | 3 146 1246| 2458 2458 24
----------------+----------------+-----------------
5 2379 2679| 1679 1469 1467| 2349 1249 8
3678 3789 4 | 15679 2 1578| 359 159 1369
68 1 269 | 569 4589 3 | 7 2459 2469
Whatever its name, we can write ...
[r1c2](-7-[r6c2]-4-[r5c2]-3-[r5c1])-7-[r123c1]=7=[r8c1]=3=[r5c1]
... which is a contradiction, because r5c1<>3 and r5c1=3 cannot both be true. Therefore, r1c2<>7. (
The contradiction might also be written as two 3s in row 5 ... or no candidates in a bivalue cell.)
There are
two implication streams for the above expression:
r1c2=7 => r6c2<>7 => r6c2=4 => r5c2<>4 => r5c2=3 => r5c1<>3
r1c2=7 => r123c1<>7 => r8c1=7 => r8c1<>3 => r5c1=3