Fiendish No. 195; 1 July

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Fiendish No. 195; 1 July

Postby Bernard Stay » Fri Jul 01, 2005 9:23 am

I'm not having a good week. I'm stuck on this puzzle after adding 11 numbers to the 25 given. I'm not alone: Pete Shaw's 'Su Doku Solver' can't do it either. Could it be misprinted? Or is it just black Friday?
Bernard Stay
 
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Joined: 22 March 2005

Postby su_doku » Fri Jul 01, 2005 11:10 am

No definitely can be done - and logically too.

Post the grid where you are stuck for a hint
su_doku
 
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Postby Bernard Stay » Fri Jul 01, 2005 11:34 am

Thanks. I'm here:-

**6|345|*91
***|***|5**
*95|7*6|**3

*21|*3*|6**
**8|*6*|9**
*69|*7*|13*

6*3|2*7|*5*
**4|6**|3**
9**|453|***
Bernard Stay
 
Posts: 94
Joined: 22 March 2005

Postby su_doku » Fri Jul 01, 2005 11:40 am

Look at column 2 - there's a pair of cells where the 3 and 4 can go. That will allow you to place a number in box 7
su_doku
 
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Postby Bernard Stay » Fri Jul 01, 2005 12:53 pm

Thanks s_d. I really should have spotted the 3/4 pairs - bad eye day. That puts a 5 in the middle of box 7 as you say, and removes the 1 from c1r8. Then what?
Bernard Stay
 
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Joined: 22 March 2005

Postby scrose » Fri Jul 01, 2005 1:29 pm

Look at where the 7's can go in column 1; make some eliminations.
Look at where the 7's can go in row 9; make some eliminations.
You will now be able to fill a cell in block 3.
scrose
 
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Postby Bernard Stay » Fri Jul 01, 2005 2:52 pm

Look at where the 7's can go in column 1; make some eliminations.
Look at where the 7's can go in row 9; make some eliminations.
You will now be able to fill a cell in block 3.


And it all comes out! Nothing but the sort of thing I've been doing everyday since New Year! As I said - a bad eye day!

But thanks folks. To the morrow!
Bernard Stay
 
Posts: 94
Joined: 22 March 2005

Postby Animator » Fri Jul 01, 2005 4:17 pm

It really is easy...

Where can it go in column 1? (Remember what you said about column 2).
What does this mean for box 7?
What does this mean for column 7?
Animator
 
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Postby su_doku » Fri Jul 01, 2005 5:59 pm

He's cracked it already Animator!


And it all comes out!
su_doku
 
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Postby Animator » Fri Jul 01, 2005 6:41 pm

Indeed... I must have mis-read that :(
Animator
 
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Postby possum » Fri Jul 01, 2005 9:01 pm

I was stuck with this one until I read the tips above.
possum
 
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Postby zahada » Mon Jul 04, 2005 9:23 pm

scrose wrote:Look at where the 7's can go in column 1; make some eliminations.
Look at where the 7's can go in row 9; make some eliminations.
You will now be able to fill a cell in block 3.


Hmm. Still struggling at this point. Could you be a little more specific?
zahada
 
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Joined: 04 July 2005

Postby Anette » Mon Jul 04, 2005 10:46 pm

Look at number 7 for columns 2 and 7.

By doing so, you willl see that it is only possible to put it in either one of 2 combinations. Either combination will make it possible for you to eliminate the 7 from all other columns for these rows.
Anette
 
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Postby zahada » Tue Jul 05, 2005 8:01 am

Anette wrote:Look at number 7 for columns 2 and 7.

By doing so, you willl see that it is only possible to put it in either one of 2 combinations. Either combination will make it possible for you to eliminate the 7 from all other columns for these rows.


Ah. Thanks, got it now.:D
zahada
 
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Joined: 04 July 2005

Postby Tom Wirschell » Wed Jul 06, 2005 12:55 pm

I don't see how Bernard Stay used the 3/4 pair clue for column 2 to come to the conclusion that there should be a 5 in the middle of box 7. Could someone perhaps elaborate?

Kind regards,

Tom Wirschell
Tom Wirschell
 
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