The New Sudoku Players' Forum

[p_court99]

So, it's the next fiendish one, and I'm stuck again.

Code: Select all

  3|5  | 82
1  |3  |   
84 |   | 
---+---+---
5 1| 43|87
 84|1 9|523
 3 | 5 |1 4
---+---+---
3  |  5| 4
4  |  6| 58
25 |4 7|6 


I've noticed that the 8th column can be narrowed to the following possibles (using the 1/3 pair):

8
(6/9)
(1/3)
-
7
2
(6/9)
-
4
5
(1/3)

Where the numbers in brackets are the possibles for those squares.

I can't find any other pairs or triples, or any mistakes but I'm totally stuck - I've spent over an hour checking and searching. Any help is much appreciated.

[Enigma]

Look for a triple of 6,7 and 9 in row 1 before eliminating them from other cells in row 1. You need to pay careful attention to box 8 in doing this.

Paul

[p_court99]

I have this in row one:

(6/7/9) (6/7/9) 3 | 5 (1/6/7/9) (1/4) | (4/7/9) 8 2

So surely the (4/7/9) possibility stops there being a 6/7/9 triple on that row?

[possum]

In box 3 the 1 has to be in row 3. This has implications for row 3 in box 2.

[su_doku]

As things stand, you can fill a number in box 2.

Look carefully at the cell where you had (1/4) again.

[p_court99]

I was able to complete the puzzle using possum's tip, thanks.

[Enigma]

Although the (4/7/9) is a possibility, 1 cannot be in r1c5 as the 1 has to be in c5 in box 8. So you could have eliminated the 7/9 from c7 leaving just the 4, which then yields 1 in c6...