Fiendish 148 Thursday 19 May

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Fiendish 148 Thursday 19 May

Postby Guest » Fri May 20, 2005 11:34 pm

I follow the discussion with the placement of 7 in Box 6 Colum 7, leading on to the pairing of 6,9 in Row 6.
Ahead of this play, however, I cannot see how to justify the 1 setting at R7C5.
Thus far my colums 5 reads:
R1C5 1/5/6/9
R2C5 7
R3C5 4
R4C5 5/6/9
R5C5 3
R6C5 2/5/6/9
R7C5 1/2
R8C5 8
R9C5 6/9

With 1 at R7C5 there follows 2 at R6C5 and hence the elimination of 2 at R6C6, leading to the 6,9 pairing in Row 6.
How to get there!
Help!
Guest
 

Postby Animator » Fri May 20, 2005 11:45 pm

Based on that information you can't place the 1...

Would it be possible that you copy the full grid?
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Postby determined » Sat May 21, 2005 12:13 am

Edward, I've been working on this puzzle today and if my memory serves me correctly, you figure out where the 2 goes by figuring out where the the 6,9 pairing is (i.e., r6c6 and r6c8). Since all other numbers besides 6 and 9 need to be eliminated from those two cells (r6c6 and r6c8), you can cross reference against the columns and rows in the puzzle to figure out where the 2 must go in Box 5. Once you know where the 2 goes, you should be able to figure out where the 1 goes, which will then help you place additional 1s and 9s in a few other Boxes.

Does this help at all?
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Postby Guest » Sat May 21, 2005 9:41 am

Puzzle 148, 19th May
Here, in response to Animator's kind interest, is the stage of completion of the full grid:
**8 2** 4**
*94 *7* 35*
*1* *4* **6

4*1 **7 *23
*2* *3* ***
*8* 1** **4

549 *** 68*
176 *8* *3*
832 **5 14*
Guest
 

Postby Guest » Sat May 21, 2005 9:50 am

Eureka
Animator - once the 2,8 numbers are locared at positions in box 3, of course, the 1 at R2C6 is fixed.
Guest
 

May 19th

Postby Dyfthegog » Sat May 21, 2005 5:16 pm

Sorry but I must be extra thick. I can usually do the Fiendish ones reasonably quickly but this one has me stumped. I can 't understand how you can put the 1 at r7c5 and a 2 at r6c5 as I have 269 at r6c6 and 579 at r6c7 and 679 at r6c8. I can't see how to get a pairing and would value guidance.
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Re: May 19th

Postby possum » Sat May 21, 2005 6:56 pm

Dyfthegog wrote:Sorry but I must be extra thick. I can usually do the Fiendish ones reasonably quickly but this one has me stumped. I can 't understand how you can put the 1 at r7c5 and a 2 at r6c5 as I have 269 at r6c6 and 579 at r6c7 and 679 at r6c8. I can't see how to get a pairing and would value guidance.


In box 3 there is a pairing of 2,8 (r2, c9 and r3, c7).
This gives us 1 in r2, c9.
Then there must be a 7 in box 6 in column 7.
In box 8. the 4 must be r 8, which puts a 4 at r 7, c 2.

The pairing of 6,9 at r5, c8 and r6, c8 leads to being able to rub out many more numbers.

Have been trying to rework the puzzle to help you. I found this one harder than usual. If you want to post the puzzle to the point that you are stuck, I'll try and help.
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Postby springman1961 » Tue May 24, 2005 10:39 pm

**82**4**
*94*7*35*
*1*84***6
4*1**7*23
*2**3****
*8*1****4
549***68*
176*8**3*
832**514*

can any one give me the next number can not find one
anywhere thank you
R B Chitty
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Postby Animator » Wed May 25, 2005 7:19 am

That's because you made a mistake... lucky it is only limited to one...

r3c4 is not the number 8.

When you fixed that then you should ook at Edward's and possum's post. these posts have the answer
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Postby Arnie » Thu May 26, 2005 8:00 pm

whilst I can see 9 can go in r5c6or 7 i do not understand why 9 cannot go in r3c8or r1c8? how have you excluded these?
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Postby Animator » Thu May 26, 2005 8:11 pm

Then you didn't look closely at box 3... I suggest you take another look at it
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Postby Arnie » Thu May 26, 2005 8:16 pm

box 3 - has a pair of 2,8 at r2c9 and r3c7
- 7 at r1c8 or r3c8
- 1 at r1c8 or 9....

....that leaves 9 to go into r 1c8 or9 or in r3c8 ?!
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Postby Animator » Thu May 26, 2005 8:29 pm

Hmm, my mistake... I really need to start paying more attention... I thought you said r3c7

But, what is your current grid? and who is telling you that you should be able to exclude the 9 from r1c8 and/or r3c8?

And did you look at the other threads about this puzzle aswell?

And, there seems to be two Arnie's posting here... Arnie and Arnie2... is it the same person or not?
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Postby Arnie » Fri May 27, 2005 5:53 am

Apologies for any confusion - I am also "Arnie 2" - when I post from work for various reasons I do not want to use a password on the company;s computer so have to log in as a guest.

I have now solved this - thanks for the tips and pointers, ...
Arnie
 
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