## Fiendish 148 Thursday 19 May

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### Fiendish 148 Thursday 19 May

I follow the discussion with the placement of 7 in Box 6 Colum 7, leading on to the pairing of 6,9 in Row 6.
Ahead of this play, however, I cannot see how to justify the 1 setting at R7C5.
Thus far my colums 5 reads:
R1C5 1/5/6/9
R2C5 7
R3C5 4
R4C5 5/6/9
R5C5 3
R6C5 2/5/6/9
R7C5 1/2
R8C5 8
R9C5 6/9

With 1 at R7C5 there follows 2 at R6C5 and hence the elimination of 2 at R6C6, leading to the 6,9 pairing in Row 6.
How to get there!
Help!
Guest

Based on that information you can't place the 1...

Would it be possible that you copy the full grid?
Animator

Posts: 469
Joined: 08 April 2005

Edward, I've been working on this puzzle today and if my memory serves me correctly, you figure out where the 2 goes by figuring out where the the 6,9 pairing is (i.e., r6c6 and r6c8). Since all other numbers besides 6 and 9 need to be eliminated from those two cells (r6c6 and r6c8), you can cross reference against the columns and rows in the puzzle to figure out where the 2 must go in Box 5. Once you know where the 2 goes, you should be able to figure out where the 1 goes, which will then help you place additional 1s and 9s in a few other Boxes.

Does this help at all?
determined

Posts: 5
Joined: 19 May 2005

Puzzle 148, 19th May
Here, in response to Animator's kind interest, is the stage of completion of the full grid:
**8 2** 4**
*94 *7* 35*
*1* *4* **6

4*1 **7 *23
*2* *3* ***
*8* 1** **4

549 *** 68*
176 *8* *3*
832 **5 14*
Guest

Eureka
Animator - once the 2,8 numbers are locared at positions in box 3, of course, the 1 at R2C6 is fixed.
Guest

### May 19th

Sorry but I must be extra thick. I can usually do the Fiendish ones reasonably quickly but this one has me stumped. I can 't understand how you can put the 1 at r7c5 and a 2 at r6c5 as I have 269 at r6c6 and 579 at r6c7 and 679 at r6c8. I can't see how to get a pairing and would value guidance.
Dyfthegog

Posts: 1
Joined: 21 May 2005

### Re: May 19th

Dyfthegog wrote:Sorry but I must be extra thick. I can usually do the Fiendish ones reasonably quickly but this one has me stumped. I can 't understand how you can put the 1 at r7c5 and a 2 at r6c5 as I have 269 at r6c6 and 579 at r6c7 and 679 at r6c8. I can't see how to get a pairing and would value guidance.

In box 3 there is a pairing of 2,8 (r2, c9 and r3, c7).
This gives us 1 in r2, c9.
Then there must be a 7 in box 6 in column 7.
In box 8. the 4 must be r 8, which puts a 4 at r 7, c 2.

The pairing of 6,9 at r5, c8 and r6, c8 leads to being able to rub out many more numbers.

Have been trying to rework the puzzle to help you. I found this one harder than usual. If you want to post the puzzle to the point that you are stuck, I'll try and help.
possum

Posts: 86
Joined: 05 April 2005

**82**4**
*94*7*35*
*1*84***6
4*1**7*23
*2**3****
*8*1****4
549***68*
176*8**3*
832**514*

can any one give me the next number can not find one
anywhere thank you
R B Chitty
springman1961

Posts: 4
Joined: 24 May 2005

That's because you made a mistake... lucky it is only limited to one...

r3c4 is not the number 8.

When you fixed that then you should ook at Edward's and possum's post. these posts have the answer
Animator

Posts: 469
Joined: 08 April 2005

whilst I can see 9 can go in r5c6or 7 i do not understand why 9 cannot go in r3c8or r1c8? how have you excluded these?
Arnie

Posts: 49
Joined: 19 May 2005

Then you didn't look closely at box 3... I suggest you take another look at it
Animator

Posts: 469
Joined: 08 April 2005

box 3 - has a pair of 2,8 at r2c9 and r3c7
- 7 at r1c8 or r3c8
- 1 at r1c8 or 9....

....that leaves 9 to go into r 1c8 or9 or in r3c8 ?!
Arnie

Posts: 49
Joined: 19 May 2005

Hmm, my mistake... I really need to start paying more attention... I thought you said r3c7

But, what is your current grid? and who is telling you that you should be able to exclude the 9 from r1c8 and/or r3c8?

And, there seems to be two Arnie's posting here... Arnie and Arnie2... is it the same person or not?
Animator

Posts: 469
Joined: 08 April 2005

Apologies for any confusion - I am also "Arnie 2" - when I post from work for various reasons I do not want to use a password on the company;s computer so have to log in as a guest.

I have now solved this - thanks for the tips and pointers, ...
Arnie

Posts: 49
Joined: 19 May 2005