Hi Bogdan,
Depending on the rating function used it might not be the case.
For example, take uniqueness-based techniques.
This puzzle posted by mith is 4.5 skfr (solves with a UR and basics).
If one of the cells of the UR had a given in it (say 6r5c9), the UR logic would no longer apply and the rating would jump to 10.8.
Of course, if one of the UR's candidates got eliminated during the solve, making one of its solutions invalid, the UR still couldn't be part of the solution, as its solutions are equivalent.
Rating functions which don't distinguish between givens and solved cells (or simply don't have avoidable rectangle implemented) would still rate it as being very hard.
Marek