The New Sudoku Players' Forum

[m_b_metcalf]

How about square root of 3 = [snip] Any Root 3 puzzlers out there ? Leren

I'll give it a shot, but not today. Mike

[m_b_metcalf]

How about square root of 3 = [snip] Any Root 3 puzzlers out there ? Leren

I'll give it a shot, but not today. Mike

First shot:

Code: Select all

 . 1 . 7 3 . 2 5 8
 7 5 . 6 8 . . . .
 8 . . . . . . . 7
 . . 7 . . . . . 2
 9 3 5 . 2 7 . 4 .
 . 4 . . 6 . 3 . .
 . . . 4 . . 1 . 5
 5 8 . . 7 . . 2 .
 3 . . . . 6 . . .

No. of givens =  32 (not possible to add zeros)

Watch this space.

[Leren]

Hodoku's solution : stte. Leren

[m_b_metcalf]

Hodoku's solution : stte. Leren

Well, yes. My goal was to pack in as many of the digits as possible. Even with fewer, the puzzles remain simple, as here:

Code: Select all

 1 . 7 . . . 3 2 5
 8 . . . . . . . 7
 . . . . . 5 . 6 8
 . . . 8 7 . . . .
 7 2 9 . . . . 3 .
 . . 5 2 . . 7 4 .
 . . . . 4 6 . . 3
 . 4 . . . . 1 5 .
 5 . . . 8 . . . .

No. of givens =  28, can add 7r9c8, cannot add zeros

Seems to be an inherent property of this series of digits.
Sorry to disappoint you.

Mike

[Leren]

Same. Apparently Power Engineering is inherently easy Leren

[Leren]

OK then, how about the Golden Ratio = 1.6180339887 4989484820 4586834365 6381177203 0917980576 2862135448 6227052604 6281890244 9707207204 1893911374 8475408807 5386891752 1266338622 (approximately).

or the largest known prime number. The record is currently held by 2^ (82,589,933) − 1 with 24,862,048 digits, found by GIMPS in December 2018. Its value is:

148894445742041325547806458472397916603026273992795324185271289425213239361064475310309971132180337174752834401423587560 ... plus a few more digits.

Leren

[m_b_metcalf]

OK then, how about the Golden Ratio = 1.6180339887 4989484820 4586834365 6381177203 0917980576 2862135448 6227052604 6281890244 9707207204 1893911374 8475408807 5386891752 1266338622 (approximately).

or the largest known prime number. The record is currently held by 2^ (82,589,933) − 1 with 24,862,048 digits, found by GIMPS in December 2018. Its value is:

148894445742041325547806458472397916603026273992795324185271289425213239361064475310309971132180337174752834401423587560 ... plus a few more digits.

Leren

GR is hopeless. It cannot have more than 26 clues, and the puzzle with the least number of solutions was;

Code: Select all

 . . . 1 . . . 6 .
 . 1 8 . . . . 3 .
 . . . 3 . 9 . 8 .
 8 . . . 7 . 4 . .
 . . . . . . . 9 8
 . 9 4 8 . . . . .
 . . . . 4 . 8 2 .
 4 . 5 . 8 . 6 . .
 . 8 3 . . . . 4 .

No. of givens =  26

brute found 98 solution(s)

The prime I'll not even try, look at those strings of repeating digits at the beginning.

Regards,

Mike

[Leren]

OK, lets get back to PI. Starting from the millionth digit it is

130927562832084531584652001027797235612923012605863536011649209902587455521403969791153402241589813245057229232332131045392469983661127509161341877972271870257744736124388514083465932031248728192989830 .......

Leren

[m_b_metcalf]

OK, lets get back to PI. Starting from the millionth digit it is

130927562832084531584652001027797235612923012605863536011649209902587455521403969791153402241589813245057229232332131045392469983661127509161341877972271870257744736124388514083465932031248728192989830 .......

Thanks for the suggestion, but this becoming tedious. Maybe someone else would like to give it a try.

Regards,

Mike

[JPF]

OK, lets get back to PI. Starting from the millionth digit it is

You should use the Champernowne constant C10 to be sure that any grid or any puzzle is hidden somewhere in its decimals.

JPF