Jasper32 wrote:I do not understand why r7c7 and r8c9 are not strong links since there is a (68) in both cells and no other (6's) or (8's) in box nine.
Hello Jasper32,
I think it's a problem with notation again. You have to bear in mind, that in nice loop notation not all implications are spelled out.
8-[R8C9]-6-[R7C7]=6 means:
if r8c9<>8 => r8c9=6
if r8c9=6 => r7c7<>6 (weak inference)
You could of course use the strong inference on 6 or 8 between r8c9 and r7c7, but that would result in a different chain.
Jasper32 wrote:And why r1c5<>5.
I suppose you meant r1c5<>3?
The chain means: if r1c5<>8 then r1c5<>3. But if r1c5=8 then r1c5<>3 as well, so no matter how you look at it, r1c5 cannot be 3.
A different nice loop for the same elimination (for practice):
r1c5 -3- r4c5 =3= r4c7 =6= r7c7 -6- r7c5 =6= r1c5 => r1c5<>3