Hi Cenoman!
Cenoman wrote:SpAce's single step is unrivaled !
Thanks! I didn't even realize how lucky that was until I started wondering why no other solutions showed up. Looks like it was the only easy one-stepper available. (There's one with a bivalue oddagon too, but it's pretty much the same).
What follows is my typical nitpicking... Hope you don't mind!
So, why not two steps of simple coloring
I like your steps but I'd rather call them X-Chains as presented. I know there's historical variance, but the de facto standard of
Simple Coloring considers only a single cluster of conjugate pairs, i.e. situations where you'd use just one tag pair in full tagging. I guess that's one reason why it's called "Simple", the other being that it uses just single digits.
Thus (standard) Simple Coloring is not a synonym for all X-Chains, and I think it's best kept that way as we don't really need two names for exactly the same thing. In this case it's available for the 3s in the second step but not for the 7s in the first. If you want to present it as a standard coloring move (instead of a Skyscraper), you could use
Multi-Coloring with two coloring clusters (tag pairs aA and bB):
- Code: Select all
.-----------------.------------------.------------------.
| 4 36 3678 | 1 9 b38-7 | 5 2 a78 |
| 2 9 b8-7 | B7-8 5 6 | 1 4 3 |
| a378 5 1 | 4 38 2 | 9 A78 6 |
:-----------------+------------------+------------------:
| 1 36 5 | 368 7 4 | 368 9 2 |
| A37 8 a367 | 9 2 5 | 36 1 4 |
| 9 4 2 | 368 1 38 | 3678 378 5 |
:-----------------+------------------+------------------:
| 5 2 9 | b38-7 4 1 | 378 6 A78 |
| 6 1 4 | 5 38 B7-38 | 2 b38-7 9 |
| 38 7 38 | 2 6 9 | 4 5 1 |
'-----------------'------------------'------------------'
Step 1. Multi-Coloring (7s): b sees both a and A => b false, B true => +7 r2c4,r8c6; -7 r1c6,r2c3,r7c4,r8c8
The second step can be done with Simple Coloring (one tag pair, aA):
- Code: Select all
.----------------.-------------------.-------------------.
| 4 a3-6 67 | 1 9 A8-3 | 5 2 78 |
| 2 9 8 | 7 5 6 | 1 4 3 |
| A7-3 5 1 | 4 a3-8 2 | 9 78 6 |
:----------------+-------------------+-------------------:
| 1 A6-3 5 | 68-3 7 4 | 368 9 2 |
| a3-7 8 67 | 9 2 5 | A6-3 1 4 |
| 9 4 2 | 68-3 1 a3-8 | 678-3 A78-3 5 |
:----------------+-------------------+-------------------:
| 5 2 9 | a3-8 4 1 | A78-3 6 78 |
| 6 1 4 | 5 A8-3 7 | 2 a3-8 9 |
| 8 7 3 | 2 6 9 | 4 5 1 |
'----------------'-------------------'-------------------'
Step 2. Simple Coloring (3s):
Wrap: duplicate 'A's (contradictions) in c7, b6 => A false (7 elims), a true (6 placements)
Traps (see both a and A): -3 r4c46, r6c7
Maybe could it be written as a one stepper, considering the second step as an almost SC of the 3s at the starting point ??
[(3)r7c4 = r7c7 - r8c8 = r6c8^ - r6c6# = r1c6 - r1c2 = r4c2] = (3)r8c6 - [(7)r8c6 = r1c6 - r1c9 = r7c9 - r7c4 = (7)r8c6] => -3 r6c4^, -3 r4c4; ste
I think that works, but the chain should be appended with "= contradiction". Otherwise it ends with a weak link, and the conclusion is hard to understand. Another way to make it more understandable (at least for me) is to reverse it:
[(7)r8c6 == (7)r8c6] - (3)r8c6 = [(3)r7c4 == (3)r6c8&r4c2] => +7 r8c6, -3 r46c4; stte
However, in that case I still see it effectively as two steps, because it starts with an independently valid AIC (resulting in +7r8c6), followed by a weak link that (truly) kills 3r8c6, resulting in the second AIC whose conclusion is what we really want. Thus, it's not really a normal single AIC with a derived strong link between two end points (or it is, but the first end point is an implied contradiction). Unfortunately I can't see another way to do it except with redundant backpedaling:
[(3)r7c4 == (3)r6c8&r4c2] = (3-7)r8c6 == (7-3)r8c6 = [(3)r7c4 == (3)r6c8&r4c2] => -3 r46c4; stte