daj95376 wrote:Where is <3> in [r3/b3] of your example?
Sorry, I should have seen that, but I took the AIC literally and didn't notice an implied (3)r3c7 = (3)r3c9.
daj95376 wrote:(6)r3c3 = (36)UR1[r38c79]+(8)r8c9 - (8=46)r12c9 => r3c79<>6
Perhaps it would be better to make it explicit:
(6)r3c3 = (36)r3c79 -aur- (36=8)r8c79 - (8=46)r12c9 ==> r3c79<>6