could anyone help me with this please

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could anyone help me with this please

Postby samuk58 » Sat May 20, 2006 5:19 am

Twenty-Five doubled=
Twelve divided by one=
3+3*3=

add all the number
...................................................................................

well that is it .......it seems simple but i gave all the obvious answers ........but all were wrong.

can anyone see a trick somewhere......

your help is appreciated
regards
Sam
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Postby MCC » Sat May 20, 2006 9:27 am

What answers have you tried?

If it's simple arithmetic, the answer should be 69.

0/100 Must do better:(
Last edited by MCC on Sat May 20, 2006 9:50 am, edited 1 time in total.
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Can anyone help me with this please

Postby Cec » Sat May 20, 2006 9:41 am

MCC wrote:If it's simple arithmetic, the answer should be 69.

Well done MCC for understanding the question:)
I'm curious to know how it is possible to calculate 3 + 3*3 = ? when the value of * is not given.

Cec
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Re: Can anyone help me with this please

Postby lunababy_moonchild » Sat May 20, 2006 10:04 am

Cec wrote:I'm curious to know how it is possible to calculate 3 + 3*3 = ? when the value of * is not given.

Cec

* doesn't have a value it's used instead of x (multiply sign). You do the equation in a certain order, if I recall correctly it's

    1 Multiply
    2 Divide
    3 Add
    4 subtract

As if there are brackets around the bit that's calculated first. If the order is wrong I'm sure that somebody will correct me.

By the way I make it 74.

Luna
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Re: could anyone help me with this please

Postby Havard » Sat May 20, 2006 10:10 am

samuk58 wrote:Twenty-Five doubled=
Twelve divided by one=
3+3*3=

add all the number
...................................................................................

well that is it .......it seems simple but i gave all the obvious answers ........but all were wrong.

can anyone see a trick somewhere......

your help is appreciated
regards
Sam


Now if it is:

(25*2) + (12/1) + (3+(3*3)) the answer is 50+12+12=74.

However, if there is a "trick", the only one I could see would be:
"Twenty-Five doubled" could actually be "20-5 doubled" or 15*2(=30)

In that case the answer is 54.

You could also have: 20-(5*2), in which case the answer is 34.

(I would go with 74 though...):)

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Postby Bigtone53 » Sat May 20, 2006 10:26 am

You do the equation in a certain order, if I recall correctly it's


1 Multiply
2 Divide
3 Add
4 subtract


In my youth, the order was BODMAS, ie brackets, of, division, multiplication, addition and subtraction.

My kid tells me that nowadays, it is BIDMAS, with the I being indices.
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Postby lunababy_moonchild » Sat May 20, 2006 11:12 am

Well now.

According to : http://www.mathsisfun.com/operation-order-bodmas.html it's

BODMAS !

B Brackets first

O Orders (ie Powers and Square Roots, etc.)

DM Division and Multiplication (left-to-right)

AS Addition and Subtraction (left-to-right)

The only strange name is "Orders". "Powers" would have been a better word, but who could remember "BPDMAS" ... ? "Exponents" is used in Canada, and so you might prefer "BEDMAS", there is also "Indices" so that makes it "BIDMAS".

In the US they say "Parenthesis" instead of Brackets, so they say "PEMDAS"


Luna *Whew!*
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Re: Can anyone help me with this please

Postby Cec » Sat May 20, 2006 11:38 am

lunababy_moonchild wrote:"...* doesn't have a value it's used instead of x (multiply sign)...."

Thanks Luna...On this basis I also make it 74. Gee! things have sure changed over the years - when I was at school an "x" signified the multiplication sign and the asterisk sign (*) used to mark words for a reference.

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Postby MCC » Sat May 20, 2006 2:02 pm

It looks like my simple arithmetic is going the way of my spelling today.

Samuk58 said he had tried all the obvious answers, I think that would mean both 3+(3x3) and (3+3)x3 in his totals.
This would mean the Twenty-Five is not the obvious 25 doubled but meaning Twenty minus Five to = 15 doubled, as Harvard as stated.
With the answer being 54.


MCC
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Re: could anyone help me with this please

Postby ronk » Sat May 20, 2006 5:28 pm

samuk58 wrote:Twenty-Five doubled=
Twelve divided by one=
3+3*3=

add all the numbers


(20 - 5 * 2) + (12 / 1) + (3 + 3 * 3) =

10 + 12 + 12 = 34

... which is an answer Havard offered as a possibility. However, I think it's actually the correct answer.
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Re: could anyone help me with this please

Postby samuk58 » Sun May 21, 2006 2:46 am

well thankyou people...
but I am afraid all those given answers are not correct......


if you know the asnwer you can win £6000...

watch ITV the mint program.........
it ran twice ..........and no one came with the right answer........

so watch ITV mint program...late at night and c if u can win £6000
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Postby Mike Barker » Sun May 21, 2006 4:22 am

There are a few more options:

Twenty-Five doubled= (20-5)*2 = 30
Twelve divided by one= 112
3+3*3= (3+3)*3 = 18

Pick your favorite combination of these and previous posts.
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Could anyone help me with this please

Postby Cec » Sun May 21, 2006 4:47 am

Mike Barker wrote:Twelve divided by one= 112

Hi Mike,
"...Just curious how you can arrive at 112?..."

Cec
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Postby Mike Barker » Sun May 21, 2006 5:04 am

if you divide (separate) the numbers "1" and "2" which make up 12 by "1" you get 112!
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Could anyone help me with this please

Postby Cec » Sun May 21, 2006 6:10 am

Thanks Mike- very imaginitive:)

Cec
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