can you solve this without using trial and error method?

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can you solve this without using trial and error method?

Postby fredooi » Tue Aug 05, 2008 3:04 am

*-----------*
|143|2..|798|
|5..|1.7|2.3|
|.2.|..8|5.1|
|---+---+---|
|432|67.|8.9|
|...|9.4|..2|
|..5|..2|476|
|---+---+---|
|..4|52.|9.7|
|25.|7.9|..4|
|.79|...|625|
*-----------*

is there any logical way to solve this? or there's only trial and error left?
got this from newspaper. hope someone can show me the way. thanks.
fredooi
 
Posts: 14
Joined: 04 August 2008

Postby daj95376 » Tue Aug 05, 2008 3:39 am

It's refreshing to have someone ask for help on a grid that can actually be solved. Too bad you didn't include a PM to show which eliminations you'd already found. So, I've included a complete solution instead of just the next step.

Code: Select all
 +-----------------------+
 | 1 4 3 | 2 . . | 7 9 8 |
 | 5 . . | 1 . 7 | 2 . 3 |
 | . 2 . | . . 8 | 5 . 1 |
 |-------+-------+-------|
 | 4 3 2 | 6 7 . | 8 . 9 |
 | . . . | 9 . 4 | . . 2 |
 | . . 5 | . . 2 | 4 7 6 |
 |-------+-------+-------|
 | . . 4 | 5 2 . | 9 . 7 |
 | 2 5 . | 7 . 9 | . . 4 |
 | . 7 9 | . . . | 6 2 5 |
 +-----------------------+

 r1  b2  Naked  Pair                     <> 56   [r23c5]
 r5  b6  Locked Candidate 1              <> 3    [r5c5]
 r9  b8  Locked Candidate 2              <> 1    [r7c6],[r8c5]
   c6b8  Locked Candidate 2              <> 3    [r8c5],[r9c45]
 r8  b9  Locked Candidate 2              <> 3    [r7c8]
   c37   X-Wing                          <> 1    [r5c258],[r8c8]
   c5    Naked  Triple                   <> 568  [r69c5]
         XY-Wing  [r5c8]/[r5c5]+[r8c8]   <> 8    [r8c5]

Note: It's common practice to skip Singles in listings. In this case, they all happen after the XY-Wing anyway.
daj95376
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Posts: 2624
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Postby fredooi » Sat Aug 09, 2008 11:16 pm

how do you figure out the way to fill in the first row, number 5 and 6?
fredooi
 
Posts: 14
Joined: 04 August 2008

Postby udosuk » Sun Aug 10, 2008 2:15 am

Code: Select all
+-----------+-----------+-----------+
|  1  4  3  |  2  .  .  |  7  9  8  |
|  5  .  .  |  1  .  7  |  2  .  3  |
|  .  2  .  |  .  .  8  |  5  .  1  |
+-----------+-----------+-----------+
|  4  3  2  |  6  7  .  |  8  .  9  |
|  .  .  .  |  9  -3 4  |  .  .  2  |
|  .  .  5  |  ?3 ?3 2  |  4  7  6  |
+-----------+-----------+-----------+
|  .  .  4  |  5  2  ?3 |  9  .  7  |
|  2  5  .  |  7  -3 9  |  .  .  4  |
|  .  7  9  |  .  .  ?3 |  6  2  5  |
+-----------+-----------+-----------+

3 of r6 must be in r6c4 or r6c5 => not in r5c5
3 of c6 must be in r7c6 or r9c6 => not in r8c5

+-----------+-----------+-----------+
|  1  4  3  |  2  .  .  |  7  9  8  |
|  5  .  .  |  1  .  7  |  2  .  3  |
|  .  2  .  |  .  .  8  |  5  .  1  |
+-----------+-----------+-----------+
|  4  3  2  |  6  7  .  |  8  .  9  |
|  .  .  ?1 |  9  -1 4  |  ?1 -1 2  |
|  .  .  5  |  .  .  2  |  4  7  6  |
+-----------+-----------+-----------+
|  .  .  4  |  5  2  .  |  9  .  7  |
|  2  5  ?1 |  7  -1 9  |  ?1 -1 4  |
|  .  7  9  |  .  .  .  |  6  2  5  |
+-----------+-----------+-----------+

1 of c3 must be in r5c3 or r8c3
1 of c7 must be in r5c7 or r8c7
=> 1 can't be in r5c5, r5c8, r8c5, r8c8

+-----------+-----------+-----------+
|  1  4  3  |  2  .  .  |  7  9  8  |
|  5  .  .  |  1  .  7  |  2  .  3  |
|  .  2  .  |  .  .  8  |  5  .  1  |
+-----------+-----------+-----------+
|  4  3  2  |  6  7  .  |  8  .  9  |
|  .  .  .  |  9 *58 4  |  . *35 2  |
|  .  .  5  |  .  .  2  |  4  7  6  |
+-----------+-----------+-----------+
|  .  .  4  |  5  2  .  |  9  .  7  |
|  2  5  .  |  7  -8 9  |  . *38 4  |
|  .  7  9  |  .  .  .  |  6  2  5  |
+-----------+-----------+-----------+

Now:
r5c8 must be 3 or 5
r8c8 must be 3 or 8
r5c5 must be 5 or 8
=> Either r5c5=8, or r8c8=8, or both of them=8
=> r8c5 can't be 8

Therefore r8c5 must be 6.

:idea:
udosuk
 
Posts: 2698
Joined: 17 July 2005

Postby fredooi » Mon Aug 11, 2008 3:00 am

thanks udosuk! your explanation is great. now i can continue solving.
fredooi
 
Posts: 14
Joined: 04 August 2008

Postby Carcul » Mon Aug 11, 2008 9:03 am

[r5c5]-5-[r5c8]-3-[r8c8]-8-[r8c5]-6-[r1c5]-5-[r5c5],

and the puzzle is solved.
Carcul
 
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Joined: 04 November 2005


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