19 posts
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Oops!! Yes I did goof on this and I deserve a kick up the backside from simes after his clear explanation on the formation of the x-wing pattern. Again I thank those who helped me and I'll stay with Angusj's description on this subject.

Regards Bonsai Cec

Regards Bonsai Cec

- Cec
**Posts:**1039**Joined:**16 June 2005

cecbevwr wrote:Hi Suduko friends. I started the following hard (very hard?) puzzle:

*4* *5* ***

**6 **2 **9

58* 1*6 ***

*6* 82* ***

8** *** **5

*** *73 *8*

*** 7*9 *24

6** 3** 9**

*** *6* *7*

I got as far as this:

*4* 957 ***

**6 4*2 **9

58* 1*6 ***

*65 82* ***

8** 69* **5

*** 573 *8*

358 719 624

6** 348 951

*** 265 *7*

Looking at Blocks 3,6 and 9, ie columns 7,8 and 9, the following

candidates exist which I think is a "X -Wing" pattern which I don't

fully understand even after reading the explanatory notes from

www.angusj.com/sudoku/hints.php:

1238 136 12368

134578 134 9

2347 34 27

1347 13479 137

12347 13469 5

124 8 126

6 2 4

9 5 1

138 7 138

I suspect candidates 1,3 and 8, which appear in each of the four

corner cells, r1c7, r1c9, r9c7 and r9c9, provide the necessary

rectangular pattern for a valid X-Wing. However, from this

point on I am stumped!! I would appreciate help in explaining

to me which candidates can be eliminated so I can proceed

further.

For what it's worth, I enjoy solving these puzzles but become

frustrated when I can't. The help I get from this forum is what

keeps me interested to learn more hints to solve these puzzles

Regards Bonsai Cec

Try this: first label columns A,B,C,D,E,F,G,H,&I and rows 1,2,3,4,5,6,7,8,&9.

The following are the steps:

I8=1

I9=3

I4=7

I3=2

I1=6

D1=9

D2=4

E3=3

E2=8

F1=7

D5=6

D6=5

D9=2

E7=1

E8=4

E5=9

A7=3

B7=5

C7=8

G7=6

H3=4

G3=7

C3=9

H6=6 (CAN ONLY BE 6)

H4=9 (CAN ONLY BE 9)

C4=5 (CAN ONLY BE 5)

G4=3 (ROW 4 CAN ONLY BE 3)

A4=4

C9=4 (BLOCK CAN ONLY BE 4)

A2=7 (COLUMN CAN ONLY BE 7)

Note 1: C1 can't be 1 since columb A1 or B2 =1 (based on A9 or B9). Since 1 is eliminated from C1, then in column C row 6 can only be 1)

Note 2: C1 can't be 2 since A6 or B6 must be 2 or 9. therefore:

C1=3 (only remaining number that can fit)

C5=7

B2=1

A1=2

B5=3

A6=9

B6=2

A9=1

B9=9

B8=7

C8=2

G2=5

H2=3

H1=8

G1=1

G9=8

H8=5

F8=8

F9=5

COMPLETE !! REGARDS DICK

- dick
**Posts:**3**Joined:**21 July 2005

19 posts
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