## Basic solving explanation.

Post the puzzle or solving technique that's causing you trouble and someone will help

### Basic solving explanation.

Hi,

Attached is the sudoku i'm dealing with.
I just want to make sure if it's accurate to say that we can get rid of the 1 in r7c1 and r7c3, based on the rectangle r5c1 r5c3 r7c1 r7c3. Is that positive?

Is that a UR?

Attachments
SUDOKUU.png (15.94 KiB) Viewed 544 times
moyk

Posts: 1
Joined: 03 September 2013

### Re: Basic solving explanation.

Almost, but wrong elimination digit/location. If neither R7C1 or R7C3 could be 5 you would have a deadly pattern on 1 and 6. Thus, one of those two cells must be 5. Because of that you can eliminate all of the other 5s in R7 and B7.

JasonLion
2017 Supporter

Posts: 641
Joined: 25 October 2007
Location: Silver Spring, MD, USA

### Re: Basic solving explanation.

moyk wrote:I just want to make sure if it's accurate to say that we can get rid of the 1 in r7c1 and r7c3, based on the rectangle r5c1 r5c3 r7c1 r7c3. Is that positive?

Yes. Because of the strong link for 6 in row 7.

Note, that no solution with digits
Code: Select all
`a . b |--------b . a |`

in UR cells (the 4 cells being in 2 rows, 2 columns and 2 boxes) can be unique, if none of the 4 digits was given.
So any candidate, which forces such a pattern, can be eliminated.

If you have no 5 in r7c13, either 1661 or 6116 is forced. So one of the 2 cells must be 5.
If you have a 1 in r7c1, then r7c3=6, r5c3=1 and r5c1=6 - deadly.
Same for r7c3=1: -> r7c1=6, r5c1=1, r5c3=6.
eleven

Posts: 2063
Joined: 10 February 2008