Basic solving explanation.

Post the puzzle or solving technique that's causing you trouble and someone will help

Basic solving explanation.

Postby moyk » Tue Sep 03, 2013 2:52 pm

Hi,

Attached is the sudoku i'm dealing with.
I just want to make sure if it's accurate to say that we can get rid of the 1 in r7c1 and r7c3, based on the rectangle r5c1 r5c3 r7c1 r7c3. Is that positive?

Is that a UR?

Thanks in advance for your help.
Attachments
SUDOKUU.png
SUDOKUU.png (15.94 KiB) Viewed 1100 times
moyk
 
Posts: 1
Joined: 03 September 2013

Re: Basic solving explanation.

Postby JasonLion » Wed Sep 04, 2013 12:34 pm

Almost, but wrong elimination digit/location. If neither R7C1 or R7C3 could be 5 you would have a deadly pattern on 1 and 6. Thus, one of those two cells must be 5. Because of that you can eliminate all of the other 5s in R7 and B7.
User avatar
JasonLion
2017 Supporter
 
Posts: 642
Joined: 25 October 2007
Location: Silver Spring, MD, USA

Re: Basic solving explanation.

Postby eleven » Sat Sep 07, 2013 11:58 am

moyk wrote:I just want to make sure if it's accurate to say that we can get rid of the 1 in r7c1 and r7c3, based on the rectangle r5c1 r5c3 r7c1 r7c3. Is that positive?

Yes. Because of the strong link for 6 in row 7.

Note, that no solution with digits
Code: Select all
a . b |
--------
b . a |

in UR cells (the 4 cells being in 2 rows, 2 columns and 2 boxes) can be unique, if none of the 4 digits was given.
So any candidate, which forces such a pattern, can be eliminated.

If you have no 5 in r7c13, either 1661 or 6116 is forced. So one of the 2 cells must be 5.
If you have a 1 in r7c1, then r7c3=6, r5c3=1 and r5c1=6 - deadly.
Same for r7c3=1: -> r7c1=6, r5c1=1, r5c3=6.
eleven
 
Posts: 3151
Joined: 10 February 2008


Return to Help with puzzles and solving techniques

cron