Hi all,
I have found, but you certainly have, that the harder a puzzle is, the less backdoors it has after it has been reduced by the basic techniques TB = { simple, closed set, alignment}. I'm talking about S-backdoor which allows to solve the puzzle with only singles after reduction by the TB.
For example, the extreme puzzle N°3 of Yzfwfs has no S-backdoor. The tarek puzzle of April 17, 2020 has 21.
Is there an established correspondence between the level of difficulty of a puzzle and the number of S-backdoors it has? Has this topic been covered?
Sincerely
Robert