The New Sudoku Players' Forum

[ArkieTech]

Code: Select all

 *-----------*
 |97.|...|.1.|
 |..2|.16|4..|
 |...|9..|...|
 |---+---+---|
 |.69|...|..2|
 |...|4.3|...|
 |3..|...|85.|
 |---+---+---|
 |...|..2|...|
 |..7|14.|6..|
 |.5.|...|.97|
 *-----------*


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[Ngisa]

Code: Select all

+---------------------+-------------------+---------------------+
| 9       7      3568 | 2358   2358    4  | 235    1       3568 |
|e58      38     2    | 3578   1       6  | 4      378     9    |
| 14568   1348   3568 | 9      23578   57 | 2357  b23678   3568 |
+---------------------+-------------------+---------------------+
| 47      6      9    | 58     58      1  | 37     347     2    |
|e2578    28     58   | 4      26      3  | 9    fa67      1    |
| 3       24     1    | 267    2679    79 | 8      5       4-6  |
+---------------------+-------------------+---------------------+
| 168     1389   368  | 57     579     2  | 135    348     3458 |
|e28      2389   7    | 1      4       59 | 6     c238     358  |
|e12      5      4    | 36     36      8  | d12    9       7    |
+---------------------+-------------------+---------------------+


(6)r5c8 = (6-2)r3c8 = r8c8 - r9c7 = (2857)r2589c1 - (7=6)r5c8 => - 6r6c9; stte

Clement

[SteveG48]

Code: Select all

 *--------------------------------------------------------------------*
 | 9      7      3568   | 2358   2358   4      | 235    1      3568   |
 | 58     38     2      | 3578   1      6      | 4     a378    9      |
 |c14     14     3568   | 9      23578  57     | 2357   23678  3568   |
 *----------------------+----------------------+----------------------|
 |c47     6      9      | 58     58     1      | 37    a347    2      |
 |c12578  128    58     | 4      26     3      | 9     b67     16     |
 | 3      124    14     | 267    2679   79     | 8      5      146    |
 *----------------------+----------------------+----------------------|
 | 6      1389   38     | 57     579    2      | 135   a348    3458   |
 | 28     2389   7      | 1      4      59     | 6     a238    358    |
 |c124    5      14     | 36     36     8      | 1-2    9      7      |
 *--------------------------------------------------------------------*


(2=3487)r2478c8 - 7r5c8 = (7142)r3459c1 => -2 r9c7 ; stte

Hmm. Clement and I don't seem to have the same starting grid. I think he didn't take the hidden pair in r3c12.

Corrected typos. Thanks, SpAce.

[SpAce]

Code: Select all

.--------------------.-------------------.------------------------.
| 9       7     3568 |  2358   2358   4  |  235     1        3568 |
| 58      38    2    | e3578   1      6  |  4      f3(7)8    9    |
| 14      14    3568 |  9      23578  57 |  2357  a[2]378-6  3568 |
:--------------------+-------------------+------------------------:
| 47      6     9    |  58     58     1  |  37      347      2    |
| 12578   128   58   |  4      26     3  |  9     f(67)      16   |
| 3       124   14   |  267    2679   79 |  8       5        146  |
:--------------------+-------------------+------------------------:
| 6      c1389  38   | d57    c579    2  | c135     348      3458 |
| 28      2389  7    |  1      4      59 |  6      b238      358  |
| 124     5     14   |  36     36     8  | b12      9        7    |
'--------------------'-------------------'------------------------'

(2)r3c8 = (21)b9p57 - (197)r7c725 = r7c4 - r2c4 = (76)r25c8 => -6 r3c8; stte

[SpAce]

(6)r5c8 = (6-2)r3c8 = r8c8 - r9c7 = (2857)r2589c1 - (7=6)r5c8 => - 6r6c9; stte

That doesn't work with the correct grid after basics. I don't know how you've managed to place 1 in r5c9, but it doesn't happen with basics alone. On the other hand, you've missed the hidden pair in box 1 (and the resulting 6r7c1), like Steve said, but it makes no difference.

[SpAce]

Hi Steve,

(2=2487)r2478c6 - 7r5c8 = (1472)r3459c1 => -2 r9c7 ; stte

That's very nice (especially compared to my long and ugly solution)! A minor typo in the first node (should be 3), though. I wouldn't normally bother mentioning it, but I've sometimes seen people try to write an AHS that way, which is clearly incorrect. You obviously didn't mean that, but it looked that way at first glance. In this case the AHS approach might in fact be slightly simpler:

(2)r8c8 = (26-7)r35c8 = (7142)r3459c1 => -2 r8c12,r9c7; stte

PS. So you've really adopted the "standard" digit order, as you said you would. Does it feel weird? To be really consistent with it, you could write the last node as (7142), because the 7 is the left-linking candidate.

[SteveG48]

That's very nice (especially compared to my long and ugly solution)! A minor typo in the first node (should be 3), though.

Thanks. I'm making a lot of typos lately. Don't hesitate to point them out. I also got the column wrong in that term.

PS. So you've really adopted the "standard" digit order, as you said you would. Does it feel weird? To be really consistent with it, you could write the last node as (7142), because the 7 is the left-linking candidate.

It does feel weird, but I'll get used to it. Agreed on the 7.